Answer:
-5(1-I) is the answer
Step-by-step explanation:
(1+2i)(1+3i)
1(1+3i)+2i(1+3i)
1+3i+2i+6i^2
As i^2=-1
1+5i+6(-1)
1-6+5i
-5+5i
Taking -5 as common
-5(1-i)
I hope this will help you :)
Answer:
6 weeks
Step-by-step explanation:
Total savings= $325
For every week, his total savings decrease by $28.
Let's form an expression for the amount of money left in his account after w weeks.
325 -28w= 157
28w= 325 -157
28w= 168
<em>Divide by 28 on both sides:</em>
w= 168 ÷28
w= 6
Thus, there are 6 weeks until he has $157.
The answer is E hope this helps
We effectively rewrite the equation as
In order for the LHS to be defined, we need to restrict 
, or 
. Now, the LHS will vanish when the numerator is 0, which happens for
This value is indeed smaller than 4, so the solution is 
.
<span><span> 17
</span><span>2 35
</span> 2
<span> 15
</span><span> 14
</span><span> 1
The remainder ends up to be 1. So it is 17.5. All you need to do, is to look for LCM in 35 and 2. </span></span>
