Both are not functions because functions cannot have repeating x values
Answer:
5
Step-by-step explanation:
(3,8) (0,4)
X1 = 3 X2 = 0
Y1 = 8 Y2 = 4
![D=\sqrt{(X1-X2)^{2}+ (Y1-Y2)^{2} }](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B%28X1-X2%29%5E%7B2%7D%2B%20%28Y1-Y2%29%5E%7B2%7D%20%20%7D)
![D= \sqrt{(3-0)^{2} + (8-4)^{2} }](https://tex.z-dn.net/?f=D%3D%20%5Csqrt%7B%283-0%29%5E%7B2%7D%20%2B%20%288-4%29%5E%7B2%7D%20%7D)
Do what's in the parentheses so...
- 3-0= 3
- 8-4= 4
Now plug it in!
![D= \sqrt{(3)^{2}+(4)^{2} }](https://tex.z-dn.net/?f=D%3D%20%5Csqrt%7B%283%29%5E%7B2%7D%2B%284%29%5E%7B2%7D%20%20%7D)
Now you are going to finish the parentheses so...
- (3)^2= 9
- (4)^2= 16
Plug that in so that you have this...
![\sqrt{9+16}](https://tex.z-dn.net/?f=%5Csqrt%7B9%2B16%7D)
Add 9+16 to get...
![\sqrt{25}](https://tex.z-dn.net/?f=%5Csqrt%7B25%7D)
Then you are going to find the number or numbers that make this a perfect square...
![\sqrt{25}= 5](https://tex.z-dn.net/?f=%5Csqrt%7B25%7D%3D%205)
So 5 is your answer
Answer:
700=700
Step-by-step explanation:
Answer: About 191 students scored between a 60 and an 80.
Step-by-step explanation:
Given : A set of 200 test scores are normally distributed with a mean of 70 and a standard deviation of 5.
i.e.
and ![\sigma=5](https://tex.z-dn.net/?f=%5Csigma%3D5)
let x be the random variable that denotes the test scores.
Then, the probability that the students scored between a 60 and an 80 :
![P(60](https://tex.z-dn.net/?f=P%2860%3Cx%3C80%29%3DP%28%5Cdfrac%7B60-70%7D%7B5%7D%3C%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%3C%5Cdfrac%7B80-70%7D%7B5%7D%29%5C%5C%5C%5C%3DP%28-2%3Cz%3C2%29%5C%20%5C%20%5B%5Cbecause%20z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3DP%28z%3C2%29-P%28z%3C-2%29%5C%20%5C%20%5B%5Cbecause%5C%20P%28z_1%3CZ%3Cz_2%29%3DP%28Z%3Cz_2%29-P%28Z%3Cz_1%29%5D%5C%5C%5C%5C%3DP%28z%3C2%29-%281-P%28z%3C2%29%29%5C%20%5C%20%5B%5Cbecause%5C%20P%28Z%3C-z%29%3D1-P%28Z%3Cz%29%5D%5C%5C%5C%5C%3D2P%28z%3C2%29-1%5C%5C%5C%5C%3D2%280.9772%29-%201%20%5C%20%5C%20%5B%5Ctext%7BBy%20z-table%7D%5D%5C%5C%5C%5C%3D0.9544)
The number of students scored between a 60 and an 80 = 0.9544 x 200
= 190.88 ≈ 191
Hence , about 191 students scored between a 60 and an 80.