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3 years ago

10

Find the value of a and b from the figure

1 answer:

siniylev [52]3 years ago

5 0

Answer:

50 is the answer

Step-by-step explanation:

b+130°=180

b=180-130

b=50°✓

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Evaluate 11/6 - 2/8=

AleksandrR [38]

Answer:

19/12

Step-by-step explanation:

4 0

2 years ago

The ingredients for making chocolate cookies are 3/4 cup of brown sugar, 1/4 cup of white sugar, 3/2 cup of butter, 11/8 cup of

Naya [18.7K]

Answer:

$\frac{51}{8}$ cups.

Step-by-step explanation:

It is given that the ingredients for making chocolate cookies are $\frac{3}{4}$ cup of brown sugar, $\frac{1}{4}$ cup of white sugar, $\frac{3}{2}$ cup of butter, $\frac{11}{8}$ cup of flour, and $\frac{5}{2}$ cup of chocolate chips.

Now, we have to calculate the total number of cups of ingredients needed in making chocolate cookies.

So, it will be given by

$(\frac{3}{4} + \frac{1}{4} + \frac{3}{2} + \frac{11}{8} + \frac{5}{2})$ cups

= $\frac{3 \times 2 + 1 \times 2 + 3 \times 4 + 11 + 5 \times 4}{8}$ cups

= $\frac{51}{8}$ cups. (Answer)

3 0

3 years ago

Evaluate the integral of the quantity x divided by the quantity x to the fourth plus sixteen, dx . (2 points) one eighth times t

Anika [276]

Answer:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c$

Step-by-step explanation:

Given

$\int\limits {\frac{x}{x^4 + 16}} \, dx$

Required

Solve

Let

$u = \frac{x^2}{4}$

Differentiate

$du = 2 * \frac{x^{2-1}}{4}\ dx$

$du = 2 * \frac{x}{4}\ dx$

$du = \frac{x}{2}\ dx$

Make dx the subject

$dx = \frac{2}{x}\ du$

The given integral becomes:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{x}{x^4 + 16}} \, * \frac{2}{x}\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{1}{x^4 + 16}} \, * \frac{2}{1}\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du$

Recall that: $u = \frac{x^2}{4}$

Make $x^2$ the subject

$x^2= 4u$

Square both sides

$x^4= (4u)^2$

$x^4= 16u^2$

Substitute $16u^2$ for $x^4$ in $\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16u^2 + 16}} \,\ du$

Simplify

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16}* \frac{1}{8u^2 + 8}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{2}{16}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

In standard integration

$\int\limits {\frac{1}{u^2 + 1}} \,\ du = arctan(u)$

So, the expression becomes:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(u)$

Recall that: $u = \frac{x^2}{4}$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c$

4 0

3 years ago

Substitute for o to solve for r

Softa [21]

Answer:

0

Step-by-step explanation:

R

3 0

3 years ago

Which number sentence is true? A. –7 + 10 = –3 B. –7 – (–10) = –17 C. 7 – 10 = 3 D. 7 – (–10) = 17

Mice21 [21]

Assignment: $\bold{Which \ Statement \ Is \ True}$

<><><><><>

Answer: $\boxed{\bold{7-\left(-10\right)}}$

<><><><><>

Explanation: $\downarrow\downarrow\downarrow$

<><><><><>

Note: $\bold{Solve \ Equation \ To \ Find \ Answer}$

[ Step One ] Apply Rule - (-a) = a

$\bold{7+10}$

[ Step Two ] Add

$\bold{17}$

<><><><><><><>

$\bold{\rightarrow Rhythm \ Bot \leftarrow}$

3 0

3 years ago

Read 2 more answers