This is a proportionality question. We have two transversals meeting at a point; the indicated congruent angles indicates the traversals intersecting parallel lines. Usually in these sorts of questions the parallel lines are on the same side of the common vertex, but here the vertex is in between, so the x is proportional to the 42.
x/6 =42/36
x = 6(42/36) = 42/6 = 7
Answer: 7
Answer:
x (x + 4) = 45
x^2 + 4x - 45 = 0
factor
(x + 9)(x - 5) = 0
x = -9 or 5
your length cannot be negative so x= 5 and x+4 =9
Step-by-step explanation:
Hope this answer is Wright
Step-by-step explanation:
solution
let,A(5,-1)
given
y=12x-1
or, y = 12 × x + (-1)
comparing it with y=mx+c
we get
x=1
y = c = -1
now
A(5,-1) and B(1,-1)
equation of line is,
(y-y1)/(x-x1) = (y2-y1)/(x2-x1)
or, (y+1)/(x-5) = (-1+1)/(1-5)
or, (y+1)/(x-5) = 0/-4
cross multiply
-4y-4 = 0
or, 0=4y+4
or, 4y+4=0 is the required eqn
I think this is the process and answer too.
I hope this helps you
Answer:
z=12
Step-by-step explanation:
It is given that x varies jointly as y and z, it means
where, k is the constant of proportionality.
It is given that x=8 when y=4 and z=9
Divide both sides by 36.
The value of k is 2/9.
We need to find the value of z when x=16 and y=6.
Substitute x=16 and y=6 in the above equation.
Multiply both sides by 3.
Divide both sides by 4.
Therefore, the value of z is 12.
Answer:200000
Step-by-step explanation:
