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omeli [17]
3 years ago
15

Fill in the blank 30.030___30.03

Mathematics
2 answers:
Goshia [24]3 years ago
6 0

Answer:

=

Step-by-step explanation:

AysviL [449]3 years ago
6 0
It’s = same thing and weight love math <33
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somebody read 50 pages of a book in 50 minutes she reads at a constant rate how many pages did she read per minute
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A cylinder and a cone have the same volume. The cylinder has radius x and height y. The cone has radius 1/3x. Find the height of
Temka [501]

Great question! I had this question in Geometry on Edmentum.

Answer: Height of cone = 3y

Step-by-step explanation:

We know that the cylinder and the cone have the same volume. The cylinder has radius x and height y. We will make use of the formulas:

Volume of cylinder = πr²h

Volume of cone = 1/3πr²h

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So, the height of the cone is equal to 3y.

Hope this helps, and have a wonderful day! :D

Please mark me brainliest! I don't have trouble getting points, but I do when it comes to brainliest.

7 0
3 years ago
8wsquared2<br><img src="https://tex.z-dn.net/?f=8w%20%7B2%20%7D%5E%7B2%7D%20%20-%2018w" id="TexFormula1" title="8w {2 }^{2} - 1
balandron [24]

{\text{Here, we have the algebraic expression}} \hfill \\ 8w \times {2^2} - 18w \hfill \\ {\text{For simplifying the expression, first we solve the exponent part,}} \hfill \\ {\text{and then the resultant will be multiply with the monomial }}18w \hfill \\ 8w \times {2^2} - 18w \hfill \\ = 8 \times w \times {2^2} - 18w \hfill \\= \left( {8 \times {2^2}} \right) \times w - 18w\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\left[ {\because \,{\text{By associative law }}a \times \left( {b \times c} \right) = \left( {a \times b} \right) \times c} \right] \hfill \\   = \left( {8 \times 4} \right) \times w - 18w \hfill \\   = 32 \times w - 18w \hfill \\= 32w - 18w \hfill \\= 14w \hfill \\

4 0
3 years ago
Choose ALL possible answers
muminat
Select all the correct answers:
1) Yes

2) No
x=8→h(8)=2(8)^2+5(8)+2=2(64)+40+2=128+40+2→h(8)=170
x=8→f(8)=3^8+2=6,561+2→f(8)=5,563>170=h(8)

3) Yes

4) No

5) Yes
rg=[g(3)-g(2)]/(3-2)=[g(3)-g(2)]/1→rg=g(3)-g(2)
g(3)=20(3)+4=60+4→g(3)=64
g(2)=20(2)+4=40+4→g(2)=44
rg=64-44→rg=20

rf=f(3)-f(2)
f(3)=3^3+2=27+2→f(3)=29
f(2)=3^2+2=9+2→f(2)=11
rf=29-11→rf=18

rh=h(3)-h(2)
h(3)=2(3)^2+5(3)+2=2(9)+15+2=18+15+2→h(3)=35
h(2)=2(2)^2+5(2)+2=2(4)+10+2=8+10+2→h(2)=20
rh=35-20→rh=15

rg=20>18=rf
rg=20>15=rh

6)  No
x=4→g(4)=20(4)+4=80+4→g(4)=84
x=4→h(4)=2(4)^2+5(4)+2=2(16)+20+2=32+20+2→h(4)=54
x=4→f(4)=3^4+2=81+2→f(4)=83>54=h(4)
f(4)=83<84=g(4)
7 0
3 years ago
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