Part a : you could draw a line from each corner to the middle
This would give you 7 triangles in total
Part b : area of one triangle : 4.5*7.8 = 35.1 / 2 = 17.55in <-- area of 1 triangle
Part c : so if there are 7 triangles and the area of 1 triangle is 17.55, you would do:
7 * 17.55 = 122.85
Sqrt -13 = sqrt13 i
sqrt -26 = sqrt2 * sqrt13i
sqrt-13 * sqrt -26 = sqrt2 * 13* i^2 = -13 sqrt2 (because i^2 = -1)
answer is -13 sqrt2
Answer:
The system has one solution.
Both lines have the same y-intercept.
The solution is the intersection of the 2 lines.
Step-by-step explanation:
Lines are
slope = 0.5
y intercept(put x =0) =5
slope = 1
y intercept(put x =0 ) =5
Both are linear equation thus they have only one solution. Also two non parallel lines meet only at one point.
If you solve these linear equation coordinate of point of intersection of line on graph will come.
Answer:
(12x²+4)(x-5)
Step-by-step explanation:
To factor the expression factor by grouping.
(12x³ - 60x²) + (4x - 20)
12x²(x - 5) 4(x-5)
(12x²+4)(x-5)
If we need our line to pass through point C, then we have to use the x and coordinates of point C in our new equation. If that line is to be perpendicular to AB, we also need to find the slope of AB and then take its opposite reciprocal. First things first. Point C lies at (6, 4) so we will use x = 6 and y = 4 in our equation in a bit. The coordinates of A are (-2, 4) and the coordinates of B are (2, -8) so the slope between them is

which is -3. The opposite reciprocal of -3 is 1/3. That's the slope we will use along with the points from C to write the new equation. We will do this by plugging in x, y, and m (slope) into the slope-intercept form of a line and solve for b.

and 4 = 2 + b. So b = 2. That's the y-intercept, the point on the y axis where the line goes through when x is 0. Therefore, the point you're looking for is (0, 2).