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babymother [125]
2 years ago
13

This is why brainly is lame

Mathematics
1 answer:
Pachacha [2.7K]2 years ago
7 0

Answer:lol so true

Step-by-step explanation:

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How do you change 36/10 to a decimal?
Elina [12.6K]
Divide 36 by 10
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4 0
3 years ago
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Given the geometric sequence where a1 = 3 and r = √2 find a9
Zigmanuir [339]

Answer:

a_9=48

Step-by-step explanation:

we are given

sequence is geometric

so, we can use nth term formula

a_n=a_1(r)^{n-1}

we have

a_1=3

r=\sqrt{2}

we have to find a9

so, we can plug n=9

we get

a_9=3(\sqrt{2})^{9-1}

a_9=2^4\cdot \:3

a_9=48

8 0
3 years ago
What is the measure of each interior angle of a regular octagon?
Anuta_ua [19.1K]

Answer:

I think the answer is Option D, 135 degrees.

Since the angles of all of the octagon combined is 1080, divide that by 8 to get 135 which means that all 8 angles are 135 degrees.

5 0
3 years ago
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The data in the table represents the average number of daylight hours each month in Springfield in 2015, rounded to the nearest
Lera25 [3.4K]
To do part B, use the equation that you wrote for part A.  We need to figure out what month number March of 2020 will be; we started in January 2015 at month 1; month 2 was Feb. 2015; month 3 was Mar. 2015; etc. to month 12 at Dec. 2015.  Then month 13 will be Jan. 2016; month 13+12=25 will be Jan. 2017; month 25+12=37 will be Jan. 2018; month 37+12=49 will be Jan. 2019; month 49+12=61 will be Jan. 2020; month 62 will be Feb. 2020; and month 63 will be March 2020.  

63 is the number you will substitute for x in the equation you've already written for part A.
8 0
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A tree is growing at a rate of 36 feet every 3
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well, we know the tree is growing at a rate of 36 feet every 3 years, how many feet is that in 1 year alone?   well, simply 36/3 = 12.

so the tree is growing 12 feet per year.

when it was first planted, it was 5 feet tall, and then after every year, we have to add 12 feet subsequently, let's do that

year 1 .......... 5 + 12(1)

year 2 .......... 5 + 12(2)

year 3 .......... 5 + 12(3)

year 4 .......... 5 + 12(4)

year 5 .......... 5 + 12(5)

year 6 .......... 5 + 12(6)

year 7 .......... 5 + 12(7)

year y .......... 5 + 12(y)

\bf \stackrel{\textit{height}}{h}~~=~~\stackrel{\textit{initial height}}{5}~~+~~\stackrel{\textit{yearly rate}}{12y} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{tree is now}}{77} = 5 + 12y\implies 72=12y\implies \cfrac{72}{12}=y\implies \boxed{6=y}

3 0
3 years ago
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