The answer is C，
as she uses SSS to prove its congruent, she uses sides instead of angles so option a and d is not correct. as it needs to prove triangle pqr is congruent to triangle sqr, its not necessary to prove PQ is equal to QR. so the answer is c
The result of rolling a number cube 7 times is a 7-digit number composed of digits 1,2,3,4,5 and 6 so that digits can repeat. The total number of possibilities is 6^7.
The number of possibilities where 4 appears exactly two times is 5^5*(7!-6!/2).
5^5 is the number of 5-digits numbers composed of digits 1,2,3,5 and 6 so that digits can repeat.
7! is the number of permutations of digits 1,2,3,4,4,5 and 6.
6! is the number of permutations of digits 1,2,3,{4,4},5 and 6.
We don't want to subtract all numbers where digits 4 appear side by side. That's why we must divide 6! by 2.
Finally, the probability is P=5^5(7!-6!/2)/7^7
The x-intercept represents the points in which the quadratic function passes through the x-axis. The maximum value represents the ordered pair with the highest range(y-value).
Interval increasing: (Negative Infinity-10)
Interval Decreasing: (10-Negative Infinity)
Part B: 8/5
Note: I am assuming the scale factor of the graph is 2.
