Answer:
160 total beads
Step-by-step explanation:
so if 1/4 of the beads are red, then 3/4 of them are not.....so 3/4 is the remainder of beads.....and 3/5 of the remainder are yellow....so 3/5 of 3/4 =
3/5 * 3/4 = 9/20...so 9/20 are yellow.....and the rest (48) are blue.
1/4 + 9/20 = 5/20 + 9/20 = 14/20 reduces to 7/10...so 7/10 of the beads are red and yellow
so if 7/10 of the beads are red and yellow, then 3/10 are blue
3/10 of what number is 48
3/10x = 48
x = 48 * 10/3
x = 480/3
x = 160
let me check it..
1/4 are red......160 total beads.....so red beads = (1/4 * 160) = 160/4 = 40
3/5 of the remainder is yellow.....so 3/5 of (160 - 40) = 3/5(120) = 72 yellow
and then u have 48 blue...
40 + 72 + 48 = 160
so there are 160 total beads.......40 red, 72 yellow, and 48 blue <===
Answer:
You add a bar till the 2 for the 9-10. You add bars till 6 for the 11- 12. You add bars till 8 for the 13-14. You add bars till the 4 for the 15-16.
Step-by-step explanation:
Answer:
(x, y) = (8, -2)
Step-by-step explanation:
Substitute:
3(-4y) + 2y = 20
-12y + 2y = 20
-10y = 20
y = -2
x = -4(-2) = 8
Answer:
In a quadratic equation of the shape:
y = a*x^2 + b*x + c
we hate that the discriminant is equal to:
D = b^2 - 4*a*c
This thing appears in the Bhaskara's formula for the roots of the quadratic equation:
You can see that the determinant is inside a square root, this means that if D is smaller than zero we will have imaginary roots (the graph never touches the x-axis)
If D = 0, the square root term dissapear, and this implies that both roots of the equation are the same, this means that the graph touches the x axis in only one point, wich coincides with the minimum/maximum of the graph)
If D > 0 we have two different roots, so the graph touches the x-axis in two different points.
