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3 years ago

Simplify the function

Mathematics

1 answer:

dusya [7]3 years ago

5 0

Answer:

Step-by-step explanation:

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12.

pashok25 [27]

Last year, the average math SAT score for students at one school was 475. The headmaster then introduced a new teaching method hoping to improve scores. This year, the mean math SAT score for a sample of students was 491. The headmaster concluded that the new teaching method produces higher SAT scores. The problem with reporting results this way is voluntary response. The information of how the teaching method isnot mentioned.

8 0

4 years ago

The area of a rectangle is 77ft and the length of the rectangle is 3ft more than double the width. Find the dimensions of the re

Radda [10]

Let b= length and a=width
Area= a*b and the problem said b=2a+3 (the length is 3ft more than double the width)
Replace b into Area formula:
Area= a*(2a+3) and we know that Area=77ft from the problem, so:
77=2a^2+3a now order and equal to zero:
2a^2+3a=77 now solve this with quadratic formula and you will get so values for a: -7ft and 5.5ft as you know the dimensions could not be negative so the correct answer for "a" side is 5.5ft, for getting the b side you haeve to replace a=5.5 into b=2a+3 and you will get b=2*5.5+3= 14ft.
Finished.

3 0

4 years ago

4−d<4+d, solve for d d>0 d>−4 d>−8 d>8

Harrizon [31]

4-2d<4
-2d>0
d>0 the answer to the question

4 0

3 years ago

Find the number that makes each statement true.

Harrizon [31]

1) 30
2) 800
3) 500
4) 4,000
5) 9
6) 600
7) 7,000
8) 200,000
9) 2,000 * 10 = 20,000. 20,000 * 10 = 200,000.

6 0

4 years ago

CAN ANYBODY HELP ME OUT

bija089 [108]

Answer:

Correct option is

b. If two sides and one included angle are equal in triangles PQS and PRS, then their corresponding sides are also equal.

Step-by-step explanation:

Here, we are given the line RQ, which is divided in two equal parts by a line PS which is perpendicular to RQ.

The foot S of PS is on the line RQ.

First of all, let us do a construction here.

Join the point R with P and P with Q.

Please refer to the attached image.

Now, let us consider the triangles PQS and PRS:

Side QS = RS (as given)

$\angle PSR = \angle PSQ = 90^\circ$

Side PS = PS (Common side in both the triangles)

Now, Two sides and the angle included between the two triangles are equal.

So by SAS congruence we can say that $\triangle PRS \cong \triangle PQS$

Therefore, the corresponding sides will also be equal.

RP = QP

RP is the distance between R and P.

QP is the distance between Q and P.

Hence, to prove that P is equidistant from R and Q, we have proved that:

b. If two sides and one included angle are equal in triangles PQS and PRS, then their corresponding sides are also equal.

7 0

3 years ago