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Vitek1552 [10]
3 years ago
11

Integrate the following: ∫

dle" class="latex-formula">
A. x^5+C
B. x^5
C. 5x^5+C
D. 5x^5
Mathematics
2 answers:
babunello [35]3 years ago
8 0

Answer:

Answer A

Step-by-step explanation:

Use the property of integrals. You now have 5 x\int\limits\,x^{4}dx where the first x next to the 5 stands for multiplication. Let's evaluate it. We get 5 (\frac{x^{5} }{5}). From here, we can simplify this into x^{5}. Add the constant of integration, which will give you the answer of x^{5} + C.

Fiesta28 [93]3 years ago
3 0

Answer:

A. x^5+C

Step-by-step explanation:

This is a great question! The first thing we want to do here is to take the constant out of the expression, in this case 5. Doing so we would receive the following expression -

5\cdot \int \:x^4dx

We can then apply the power rule " \int x^adx=\frac{x^{a+1}}{a+1} ", where a = exponent ( in this case 4 ),

5\cdot \frac{x^{4+1}}{4+1}

From now onward just simplify the expression as one would normally, and afterward add a constant ( C ) to the solution -

5\cdot \frac{x^{4+1}}{4+1}\\ - Add the exponents,

5\cdot \frac{x^{5}}{5} - 5 & 5 cancel each other out,

x^5 - And now adding the constant we see that our solution is option a!

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mote1985 [20]

As razões que se aplicam são as seguintes:

“São 4 hambúrgueres

vendidos para cada 3 cheeseburgers vendidos na cafeteria." A proporção de

hambúrgueres vendidos para cheeseburgers vendidos é de 4:3.

"Há 20 notas de aprovação para cada 25 testes de matemática classificados.

A proporção de escores de aprovação para testes classificados é de 4:5."

5 0
3 years ago
4-It has been a bad day for the market, with 70% of securities losing value. You are evaluating a portfolio of 20 securities and
riadik2000 [5.3K]

Answer:

b) 0.0007

c) 0.4163

d) 0.2375

Step-by-step explanation:

We are given the following:

We treat securities lose value as a success.

P(Security lose value) = 70% = 0.7

Then the securities lose value follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 20.

a) Assumptions

  • There are 20 independent trials.
  • Each trial have two possible outcome: security loose value or security does not lose value.
  • The probability for success of each trial is same, p = 0.7

b) P(all 20 securities lose value)

We have to evaluate:

P(x = 20)\\= \binom{20}{0}(0.7)^0(1-0.7)^{20}\\= 0.0007

0.0007 is the probability that all 20 securities lose value.

c) P(at least 15 of them lose value.)

P(x \geq 15)\\= P(x=15) + P(x = 16) + P(x=17) + P(x=18) +P(x = 19) +P(x = 20)\\ \binom{20}{15}(0.7)^{15}(1-0.7)^{5} +...+ \binom{20}{20}(0.7)^{20}(1-0.7)^{0} \\=0.4163

d) P(less than 5 of them gain value.)

P(gain value) = 1 - 0.7 = 0.3

P(x < 5)\\= P(x=0) + P(x = 1) + P(x=2) + P(x=3) +P(x = 4)\\ \binom{20}{0}(0.3)^{0}(1-0.3)^{20} +...+ \binom{20}{4}(0.3)^{4}(1-0.3)^{16} \\=0.2375

7 0
3 years ago
PLZ HURRY!!! NEED ANSWERS FAST!!!!
Vladimir79 [104]

I think it is the first one.

7 0
3 years ago
Read 2 more answers
Solve for m: m/3 + 10 =15
Nat2105 [25]

Answer:

m=15

Step-by-step explanation:

8 0
3 years ago
What is the GCF of 26 48 62
Bingel [31]
What factors to they have in common?

First, they're all even, so 2

if we divide all of them by 2, we get:
13,24,31

now, 13,31 are primes: so that means that those numbers don't have any more common factors!

So the greatest Common Factor of those 3 numbers is 2.
8 0
3 years ago
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