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2 years ago

14

The radioactive substance cesium-137 has a half-life of

1 answer:

statuscvo [17]2 years ago

7 0

A(t)=A0*(1/2)^(t/30)
where t=elapsed years
A0=initial mass at t=0.

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3 years ago

Write 1-2log7x as a single logarithm

slavikrds [6]

Answer:

$log_{7} \frac{7}{x^{2} }$

Step-by-step explanation:

We need to write $1 - 2log_{7}x$ as a single logarithm.

We know that

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Therefore we have:

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3 years ago