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jasenka [17]
2 years ago
5

Are the leap years divisible by 2​

Mathematics
1 answer:
Helen [10]2 years ago
8 0
Any year that is evenly divisible by 4 is a leap year.
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3 2/6 + ( 2 1/6 + 4/6 )
stellarik [79]

Answer:

5 7/6 or 6 1/6 either one works they are the same number just one is not simplified

3 0
3 years ago
Find the solution set of the inequality<br> 12 - 6x &gt; 24.
Hoochie [10]

Answer:

x < -2

Step-by-step explanation:

12 - 6x > 24       Equation

-6x > 12        Subtract 12 from both sides

x < -2        Divide both sides from -2, if you divide by any negative number in an inequality you have to switch the sign

3 0
3 years ago
Read 2 more answers
Write the equation for the circle with center (1, 1) and radius 5.
zepelin [54]
The answer is C
(x-h)^2 + (y -k)^2 =r^2
Center (h,k) r = radius
4 0
3 years ago
If f(x)=-3+7 and g(x)=-7+3, what is the value of f(-3) - g(3)
Andreyy89
F(x) = -3 + 7 = 4
g(x) = -7 + 3 = -4

f(-3) - g(3) = 4 - (-4) = 4 + 4 = 8
6 0
3 years ago
The probability distribution of random variable, X, is defined as follows:
stealth61 [152]

Answer and Step-by-step explanation:

A) For the model to be a probability distribution, it has to follow two conditions:

1) The probability of each value of the discrete random variable is between, and included, 0 and 1:

2) The sum of all probabilities is 1;

In the table shown, the probabilities are from 0 to 0.3 - between 0 and 1;

Adding the probabilities: 0 + 0.3 + 0.1 + 0.3 + 0.3 = 1

Therefore, this model is a valid probability distribution model.

B) They are discrete because each value correspond to a finite number of possible values.

C) Expected value is calculated by

E(X) = \Sigma xP(x)

E(X) = 0.0 + 1*0.3 + 2*0.1 + 3*0.3 + 4*0.3

E(X) = 2.6

D) P(X=3) = P(3), which means probability of 3:

P(X=3) = 0.3

E) P(X<4): probabilities of values of X that are less than 4:

P(X<4) = P(0) + P(1) + P(2) + P(3)

P(X<4) = 0 + 0.3 + 0.1 + 0.3

P(X<4) = 0.7

F) P(X>0) = P(1) + P(2) + P(3) + P(4)

P(X>0) = 0.3 + 0.1 + 0.3 + 0.3

P(X>0) = 1

G) P(X=5) = P(5)

There is no probability of P(5) because the model doesn't "cover" that number.

H) P(X=0) = P(0)

P(X=0) = 0

I) The total area of any density curve is 1 because it represents all the possible values a variable can assume.

3 0
3 years ago
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