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mario62 [17]
3 years ago
6

Simultaneous equation Find x and y 2x+y=5 X+3y=5

Mathematics
2 answers:
snow_tiger [21]3 years ago
6 0
x+3y=5 \ =>\boxed{x=5-3y} \\\\ 2x+y=5 \\\\ 2(5-3y)+y=5 \\\\10-6y+y=5 \\\\ -5y=5-10 \\\\ -5y=-5 \ |:(-5) \\\\ \boxed{y=1} \\\\ x=5-3*1 \\\\ x=5-3 \\\\ \boxed{x=2}
dlinn [17]3 years ago
4 0
Elimination\ method:\\  \left\{\begin{array}{ccc}2x+y=5\\x+3y=5&|multiply\ both\ sides\ by\ (-2)\end{array}\right\\+\left\{\begin{array}{ccc}2x+y=5\\-2x-6y=-10\end{array}\right\ \ \ |add\ sides\ of\ the\ equations\\------------\\.\ \ \ \ -5y=-5\ \ \ \ \ |divide\ both\ sides\ by\ (-5)\\.\ \ \ \ \ \ \ \boxed{y=1}\\\\substitute\ the\ value\ of\ y\ into\ one\ of\ the\ equations\ (\#2)\\\\x+3\times1=5\\x+3=5\ \ \ \ \ \ |subtract\ 3\ from\ both\ sides\\\boxed{x=2}\\\center\boxed{Answer:x=2\ and\ y=1\to(2;\ 1)}
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Your friend is trying to see if you can guess the two numbers she secretly has written on her paper. Your friend tells you that
DaniilM [7]

Hello,

First we work out the equations:

x + y =62 will be the first equation.

2x= y +13 is the second equation.

We can first rewrite the second equation as 2x – y =13.

So we have:

x + y = 62

2x –y =13

KEEP IN MIND: With y being positive in one of the equations and negative in the other, we can combine the equations to quickly eliminate y and solve for x.

x + y = 62

+2x –y =13

3x = 75 divide both sides by 3 to get x.

x = 25

Now that we have x we can substitute the value for x, 25.

25 + y = 62 we can subtract 25 from both sides to get y.

y = 62- 25

y = 37

2(25) = 37 + 13

Therefore,

50 = 50

Have a amazing day.

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3 years ago
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3 years ago
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lubasha [3.4K]

Answer:

Step-by-step explanation:

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Answer:

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