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3 years ago

1. How many grams of NaOH are in 400.0 mL of a 0.5 M solution of NaOH?

1 answer:

3 0

1. molarity = (moles)/vol in litres
0.5=[(weight/40)*1000]/4
0.5 = weight/16
weight of NaOH = 8 grams

2. weight = 0.45*850*84/100 gms
molecular weight = 85m (not sure abt this)

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Answer:

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Explanation:

Let the molecular mass of an organic solid be $C_xH_yO_z$

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$Delta T_b=K_b\times \frac{\text{Mass of solid}}{\text{Molar mass of solid}\times \text{Mass of diphenyl in Kg}}$

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$K_b$ = boiling point constant = 8.00 °C/m

m = molality

Now put all the given values in this formula, we get

$1.5^oC=8.00 ^oC/m\times \frac{0.561 g}{\text{Molar mass of solid}\times 0.0249 kg}$

${\text{Molar mass of solid}}=120.16 g/mol$

$\%=\frac{\text{Number of atoms}\times \text{mass of an atom}}{\text{molas mass of compound}}\times 100$

Percentage of carbon in an organic solid = 40.0%

$40\%=\frac{x\times 12 g/mol}{120.16 g/mol}\times 100$

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Percentage of hydrogen in an organic solid = 6.7%

$6.7\%=\frac{y\times 1 g/mol}{120.16 g/mol}\times 100$

y = 8.0

Percentage of hydrogen in an organic solid = 6.7%

$53.3\%=\frac{x\times 12 g/mol}{120.16 g/mol}\times 100$

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The molecular formula of an organic solid is $C_4H_8O_4$

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