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Stells [14]
3 years ago
15

Which three groups of the periodic table contain the most elements classified as metalloids (semimetals)?

Chemistry
2 answers:
attashe74 [19]3 years ago
8 0
The metalloids are mostly concentrated in groups 14, 15, and 16. (Some simpler charts will show them as 4A, 5A, and 6A - take a look at the top of the periodic table your class uses to double-check).

If you like my answer, please vote me a 'brainliest' - trying to improve my rank :-)

andrey2020 [161]3 years ago
5 0

Answer:

The metalloids are mostly concentrated in groups 14, 15, and 16. (Some simpler charts will show them as 4A, 5A, and 6A - take a look at the top of the periodic table your class uses to double-check).

If you like my answer, please vote me a 'brainliest' - trying to improve my rank :-)

Explanation:

what they said

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Competition is rivalry between individuals for a particular resource.
djyliett [7]

Answer:

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5 0
3 years ago
Read 2 more answers
When 0.243 g of Mg metal is combined with enough HCl to make 100 mL of solution in a constant-pressure calorimeter, the followin
satela [25.4K]

Answer:

ΔH = - 464 kJ/mol  

Explanation:

Step 1: Data given

Mass of Mg = 0.243 grams

volume of solution = 100 mL

Initial temperature = 23.0 °C

Final temperature = 34.1 °C

Specific heat = 4.18 J/g°C

Step 2: Calculate the heat transfer

Q= m*c*ΔT

⇒ m = the mass of the solution = 100 grams

⇒ c = the specific heat of the solution = 4.18 J/g°C

⇒ ΔT = The change in temperature = T2 - T1 = 34.1 - 23.0 = 11.1 °C

Q = 100 g * 4.18 J/g°C * 11.1°C

Q = 4639.8 J

Step 3: Calculate moles of Mg

Moles Mg = 0.243 grams / 24.3 g/mol

Moles Mg = 0.01 moles

Step 4: Calculate  ΔH

ΔH = 4639.8 J / 0.01 moles

ΔH = 463980 J/mol = 464 kJ/mol

(4.6398 kJ) / (0.0099979 mol) = 464 kJ/mol  

Since the reaction is exothermic, the ΔH is negative by convention, so:

ΔH = - 464 kJ/mol  

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