Given z=f(x,y),x=x(u,v),y=y(u,v), with x(1,3)=2 and y(1,3)=2, calculate zu(1,3) in terms of some of the values given in the tabl
stich3 [128]
The value of zu(1,3) using the data elements represented on the table of values is q + p
<h3>How to solve the calculus expression?</h3>
The given parameters are:
z = f(x, y)
x = x(u, v)
y = y(u, v)
Where
x(1, 3) = 2 and y(1, 3) = 2
To calculate zu(1,3), we make use of:
The values x(1, 3) = 2 and y(1, 3) = 2 mean that:
(x,y) = (2,2).
So, we have:
From the table of values, we have:
So, the equation becomes
Evaluate the product
Hence, the value of zu(1,3) is q + p
Read more about calculus at:
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I do not know how to show the working out but its 4+6+6
From what i see it could be
Exact form: 6 square root 5/ 5
Decimals: 2.68
That's very interesting. I had never thought about it before.
Let's look through all of the ten possible digits in that place,
and see what we can tell:
-- 0:
A number greater than 10 with a 0 in the units place is a multiple of
either 5 or 10, so it's not a prime number.
-- 1:
A number greater than 10 with a 1 in the units place could be
a prime (11, 31 etc.) but it doesn't have to be (21, 51).
-- 2:
A number greater than 10 with a 2 in the units place has 2 as a factor
(it's an even number), so it's not a prime number.
-- 3:
A number greater than 10 with a 3 in the units place could be
a prime (13, 23 etc.) but it doesn't have to be (33, 63) .
-- 4:
A number greater than 10 with a 4 in the units place is an even
number, and has 2 as a factor, so it's not a prime number.
-- 5:
A number greater than 10 with a 5 in the units place is a multiple
of either 5 or 10, so it's not a prime number.
-- 6:
A number greater than 10 with a 6 in the units place is an even
number, and has 2 as a factor, so it's not a prime number.
-- 7:
A number greater than 10 with a 7 in the units place could be
a prime (17, 37 etc.) but it doesn't have to be (27, 57) .
-- 8:
A number greater than 10 with a 8 in the units place is an even
number, and has 2 as a factor, so it's not a prime number.
-- 9:
A number greater than 10 with a 9 in the units place could be
a prime (19, 29 etc.) but it doesn't have to be (39, 69) .
So a number greater than 10 that IS a prime number COULD have
any of the digits 1, 3, 7, or 9 in its units place.
It CAN't have a 0, 2, 4, 5, 6, or 8 .
The only choice that includes all of the possibilities is 'A' .
Answer:300
Step-by-step explanation:
um i dk know if the two 50$ means any thing but thats what i got
