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3 years ago

What is the factored or of 25y^4 - 4z^2

Mathematics

1 answer:

Cerrena [4.2K]3 years ago

5 0

Answer:

$(5y^2+2z)(5y^2-2z)$

Step-by-step explanation:

Use the difference of squares formula.

$a^2-b^2=(a+b)(a-b)$

$a=5y^2 \\ b=2z$

$(5y^2+2z)(5y^2-2z)$

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Please help me, this is PEDMAS

rusak2 [61]

Answer:

1). 183

2). 83

3). 353

4). -2652

5). 59

6). 510

7). -293

8). 79

9). 78

10). 87

Step-by-step explanation:

Considering order of operation, parenthesis must be simplified first.

The solutions to the given questions are shown below;

$1). \ \ 5+(7\times (3+2)^2) + 3=8 + (7\times (5)^2) = 8 + (7\times 25) = 8 + 175 = 183$

$2). \ 16+(8+ (6+2)^2) - 5=16-5 + (8+ (8)^2) = 11 + (8+64) = 11 + 72 = 83$

$3). \ (15+ 3)^2 + ((14+6)+3^2)= (18)^2 + ((20) + 9) = 324 + (29) = 353$

$4). \ ((11+ 2)-(24+2)^2)\times 2^2 = (13 - 676) \times 4 = (-663)\times 4 = -2652$

$5). \ ((4+3)^2+ 6) -5+3^2= (49 + 6) - 5 + 9= (49+6+9) - 5 = 64-5 = 59$

$6). \ (20+ 2)^2 +((15+7)+2^2)= (484) + (22+ 4)= 484 + 26 =510$

$7). \ ((12 + 4)- (15+3)^2+ 5^2 = (16 - 324) + 25 = -318 + 25 = -293$

$8). \ (6^2+ (24+ 3+5^2)) - 3^2= (36 + (52)) - 9 = (88) - 9 = 79$

$9). \ ((10-4)^2\times 2) + 2 + 2^2= ((6)^2 \times 2) + 2 + 4 = (36\times 2)+ 6 = 72 + 6 = 78$

$10). \ (7^2 + (16 + 8 + 2^2)) + 3^2 = (49 + 28) + 9 = 78 + 9 = 87$

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3 years ago

Plz helllppp.. Ill mark as brainliest to who hepls. :3 ThankU m8

julia-pushkina [17]

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Vanyuwa [196]

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**FIRST CORRECT ANSWER GETS BRAINLEST**