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guajiro [1.7K]
3 years ago
11

Helpppppppppppppppppppppppp

Mathematics
1 answer:
nlexa [21]3 years ago
6 0

Answer:

\frac{3(5 + 8) - 9 {}^{2} }{4 + 3} \\  \frac{15 + 24 - 9 {}^{2} }{7}  \\ \frac{93 + 9 {}^{2} }{7}  \\  \frac{93 + (9 \times 9)}{7} \\  \frac{93 + 81}{81}  \\  \frac{174}{7}  \\ 24.85 \: \:  \:  \: . answer

Step-by-step explanation:

<h2>please mark me brainliest please.</h2>
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Use the net as an aid to compute the surface area of the triangular prism. A) 112 m2 B) 136 m2 C) 160 m2 D) 184 m2
Aloiza [94]

Answer:

136 m2 Option c

Step-by-step explanation:

136 m2

1 base = 6 × 7 = 42

2 sides = 2(7 × 5) = 70

2 triangles = 2(6 × 4

2

) = 24

SA = 42 + 70 + 24 = 136 m2

7 0
3 years ago
Read 2 more answers
Pls help urgently extra points and mark brainlist
Andreas93 [3]

Answer:

7

Step-by-step explanation:

9 is not a prime factor and of you divide 210 with 11, it will be a decimal

5 0
3 years ago
Please help me to solve this ​
natka813 [3]
5) all you have to do is calculate which would be 2.9166...
6) 65.898
6 0
3 years ago
Read 2 more answers
Find the area of ABC with vertices A(3,-6), B(5,-6), and C(7,–9).
stellarik [79]

Area of a triangle ABC with the given vertices is 3 square units.

Given that, the vertices of a triangle ABC, A(3,-6), B(5,-6), and C(7,–9).

<h3>What is the area of triangle formula in coordinate geometry?</h3>

In Geometry, a triangle is a three-sided polygon that has three edges and three vertices. The area of the triangle is the space covered by the triangle in a two-dimensional plane.

Area of a triangle = \frac{1}{2} ( |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|)

Here, (x1, y1) = A(3,-6), (x2, y2) = B(5,-6), and (x3, y3) = C(7,–9)

Now, the area of a triangle = 1/2 (|3(-6+9)+5(-9+6)+7(-6+6)|)

= 1/2 (|3(3)+5(-3)+7(0)|)

= 1/2 (|(9-15)|)

= 1/2 × 6

= 3 square units

Therefore, area of a triangle ABC with the given vertices is 3 square units.

To learn more about the area of a area of triangle with vertices visit:

brainly.com/question/26633662.

#SPJ1

7 0
2 years ago
11 m
liubo4ka [24]

first off let's notice that the height is 11 meters and the volume of the cone is 103.62 cubic centimeters, so let's first convert the height to the corresponding unit for the volume, well 1 meters is 100 cm, so 11 m is 1100 cm.

\textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ V=\stackrel{cm^3}{103.62}\\ h=\stackrel{cm}{1100} \end{cases}\implies 103.62=\cfrac{\pi r^2 (1100)}{3} \\\\\\ 3(103.62)=1100\pi r^2\implies \cfrac{3(103.62)}{1100\pi }=r^2 \\\\\\ \sqrt{\cfrac{3(103.62)}{1100\pi }}=r\implies \stackrel{cm}{0.00510199305952} \approx r

6 0
2 years ago
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