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Degger [83]
3 years ago
6

The midpoint of AB is M(1, 1). If the coordinates of A are (3, -3), what are the coordinates of b

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
6 0

Answer:

Midpoint is ( Average of x’s, Average of y’s )

1 = (x + 7)/2

2 = x + 7, x = - 5

and - 1 = (y + (-4))/2

so - 2 = y - 4 and y = 2

Pt B = (- 5, 2)

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THE X-INTERCEPT OF THE LINE X=3.5 IS
tiny-mole [99]
Well.. for the equation x= 3.5, let's take a look at its values
\bf \begin{array}{lrlll}
x&y\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
3.5&-\infty\\
3.5&-1,000,000\\
3.5&-1,000\\
3.5&-100\\
3.5&-10\\
3.5&-1\\
3.5&0\\
3.5&1\\
3.5&10\\
3.5&100\\
3.5&1,000\\
3.5&1,000,000\\
3.5&1+\infty
\end{array}

so.. notice.. no matter what "y" is, "x"  will always be 3.5,
so is really just a horizontal line, thus, look at the picture below

8 0
4 years ago
(3x5)-1 expression word
pshichka [43]

Answer:

Subtract the result of three times five with 1.

Step-by-step explanation:

(3 \times 5)-1

15-1

14

Subtract the result of three times five with 1.

4 0
3 years ago
G(a) = 3a + 2<br> f(a)=2a-4<br> Find (g/f)(3)
Basile [38]

Answer:(gf)(3)=g(3)f(3) g(a)=3a+2 or g(3)=3(3)+2=9+2 =11 f(a)=2a−4 f(3)=2(3)−4=6−4=2 g(3)f(3)=112. Answer  

Step-by-step explanation:

7 0
2 years ago
How many zeroes do we write when we write all the integers 1 to 243 in base 3?
Monica [59]

Answer:

289 numbers

Step-by-step explanation:

Above you will find the list of integers from 1 to 243 in base 3:

(1, 2, 10, 11, 12, 20, 21, 22, 100, 101, 102, 110, 111, 112, 120, 121, 122, 200, 201, 202, 210, 211, 212, 220, 221, 222, 1000, 1001, 1002, 1010, 1011, 1012, 1020, 1021, 1022, 1100, 1101, 1102, 1110, 1111, 1112, 1120, 1121, 1122, 1200, 1201, 1202, 1210, 1211, 1212, 1220, 1221, 1222, 2000, 2001, 2002, 2010, 2011, 2012, 2020, 2021, 2022, 2100, 2101, 2102, 2110, 2111, 2112, 2120, 2121, 2122, 2200, 2201, 2202, 2210, 2211, 2212, 2220, 2221, 2222, 10000, 10001, 10002, 10010, 10011, 10012, 10020, 10021, 10022, 10100, 10101, 10102, 10110, 10111, 10112, 10120, 10121, 10122, 10200, 10201, 10202, 10210, 10211, 10212, 10220, 10221, 10222, 11000, 11001, 11002, 11010, 11011, 11012, 11020, 11021, 11022, 11100, 11101, 11102, 11110, 11111, 11112, 11120, 11121, 11122, 11200, 11201, 11202, 11210, 11211, 11212, 11220, 11221, 11222, 12000, 12001, 12002, 12010, 12011, 12012, 12020, 12021, 12022, 12100, 12101, 12102, 12110, 12111, 12112, 12120, 12121, 12122, 12200, 12201, 12202, 12210, 12211, 12212, 12220, 12221, 12222, 20000, 20001, 20002, 20010, 20011, 20012, 20020, 20021, 20022, 20100, 20101, 20102, 20110, 20111, 20112, 20120, 20121, 20122, 20200, 20201, 20202, 20210, 20211, 20212, 20220, 20221, 20222, 21000, 21001, 21002, 21010, 21011, 21012, 21020, 21021, 21022, 21100, 21101, 21102, 21110, 21111, 21112, 21120, 21121, 21122, 21200, 21201, 21202, 21210, 21211, 21212, 21220, 21221, 21222, 22000, 22001, 22002, 22010, 22011, 22012, 22020, 22021, 22022, 22100, 22101, 22102, 22110, 22111, 22112, 22120, 22121, 22122, 22200, 22201, 22202, 22210, 22211, 22212, 22220, 22221, 22222, 100000)

If you count them, you will find that there are 289 numbers in total!

8 0
4 years ago
Match each operation involving f(x) and g(x) to its answer
eimsori [14]

Answer:

(g-f) (-1)= sqrt(15)

(f/g)(-1)= 0

(g+f)(2)=sqrt(3)-3

(g*f)(2)=-3*sqrt(3)

Step-by-step explanation:

We have to eval the expressions given in the point indicated.

Lets start by the first equation

(g-f)(-1)= g(-1) - f(-1)= \sqrt{11-4*(-1)}    - 1 +(-1)^{2} = \sqrt{15}

Now, lest continue with the others

(f/g)(-1)= f(-1)/g(-1)= (1-1)/sqrt(15)=0

(g+f)(2)=g(2)+f(2)=sqrt(3)-3

(g*f)(2)=g(2)*f(2)=sqrt(3)*(-3)=-3sqrt(3)

3 0
3 years ago
Read 2 more answers
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