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Gnesinka [82]
3 years ago
11

∠1 and ∠2 are vertical angles. If m∠1 = (17x + 1)° and m∠2 = (20x – 14)°, find m∠2. Answer with "m∠2=_"

Physics
1 answer:
Bingel [31]3 years ago
8 0

Answer:

m<2 = 86

Explanation:

Vertical angles means the angles are equal to each other so:

<1 = <2

17x + 1 = 20x - 14

17x - 20x = -14 - 1

-3x = -15

x = 5

m<2:

20x - 14

20(5) - 14

100 - 14

86

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yuradex [85]

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Explanation:

It's common knowledge.

7 0
3 years ago
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bulgar [2K]

Hello,

1 inch = 2 centimeters

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7 0
3 years ago
Please I need help........
LenKa [72]

Answer:

7.46 J/kg/K

Explanation:

The heat absorbed or lost is:

q = mCΔT

where m is the mass, C is the heat capacity, and ΔT is the change in temperature.

Given q = 15.0 J, m = 0.201 kg, and ΔT = 10.0 °C:

15.0 J = (0.201 kg) C (10.0 °C)

C = 7.46 J/kg/°C

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7 0
3 years ago
Read 2 more answers
2/25/20 or 2/28/20 Dispatch #53
mixer [17]

Answer:

Power = 21[W]

Explanation:

Initial data:

F = 35[N]

d = 18[m]

In order to solve this problem we must remember the definition of work, which tells us that it is equal to the product of a force for a distance.

Therefore:

Work = W = F*d = 35*18 = 630 [J]

And power is defined as the amount of work performed in a time interval.

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3 0
3 years ago
To calibrate the calorimeter electrically, a constant voltage of 3.6 V is applied and a current of 2.6 A flows for a period of 3
iren [92.7K]

Answer:

372.3 J/^{\circ}C

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First of all, we need to calculate the total energy supplied to the calorimeter.

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V = 3.6 V is the voltage applied

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P=VI=(3.6)(2.6)=9.36 W

Then, this power is delivered for a time of

t = 350 s

Therefore, the energy supplied is

E=Pt=(9.36)(350)=3276 J

Finally, the change in temperature of an object is related to the energy supplied by

E=C\Delta T

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C is the heat capacity of the object

\Delta T =29.1^{\circ}-20.3^{\circ}=8.8^{\circ}C is the change in temperature

Solving for C, we find:

C=\frac{E}{\Delta T}=\frac{3276}{8.8}=372.3 J/^{\circ}C

5 0
3 years ago
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