Answer:
F=5449 N
Explanation:
Work done is a product of force and displacement ie
Work done, W, = Force*Displacement
Power, P, is Work done/Time
where P is power, W is work done, F is force, S is displacement and t is time
In this case, F is the frictional force. Converting the power from hp to W, we multiply by 746 hence P=746*168=125328 W
Since displacement/time is velocity, then
P=FV where V is velocity in m/s
Making F the subject
F=5449 N
Answer:
60m/s
Explanation:
initial energy = final energy
g.p.e = k.e
k.e = 0.5 × mass × velocity²
g.p.e = 990000J as per Question
990000Nm = 0.5 × 550 × V²
V² = 3600
V = 60m/s
The energy of a light wave is calculated using the formula
E = hc/λ
h is the Planck's constant
c is the speed of light
λ is the wavelength
For the ir-c, the range is
<span>6.63 x 10^-34 (3x10^8) / 3000 = 6.63 x 10 ^-29 J
</span>6.63 x 10^-34 (3x10^8) / 1000000 = 1.99 x 10^-31 J
For the ir-a, the range is
6.63 x 10^-34 (3x10^8) / 700 = 2.84 x 10^-28 J
6.63 x 10^-34 (3x10^8) / 1400 = 1.42 x 10^-28 J
Answer: 0.107
Explanation:
We can solve this problem with Kepler's Third Law of Planetary motion:
(1)
Where:
is the orbital period of Phobos around Mars
is the Gravitational Constant
is the mass of Mars
is the semimajor axis of the orbit Phobos describes around Mars (assuming it is a circular orbit, the semimajor axis is equal to the radius of the orbit)
Well, firstly we have to convert the orbital period to seconds:
Now, we have to find from (1):
(2)
(3)
(4) This is the mass of Mars
On the other hand, it is known the mass of the Earth is:
(5)
Then, if we want to know the ratio of Mars’s mass to the mass of the earth, we have to divide by 
:
Finally:
