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Allushta [10]
3 years ago
10

Evaluate the expression below when X = 4 and y = (-3) 4x + 2xy

Mathematics
1 answer:
zepelin [54]3 years ago
7 0

Step-by-step explanation:

4x + 2xy=

4×4 + 2×4×-3

= 16 + (-24)

= - 8

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Find the volume of the cylinder. Round your answer to the nearest tenth.
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Answer:

4948

Step-by-step explanation:

volme of a cylinder= πr^{2}×h

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Please help me with these. These are so hard.<br><br>​
LuckyWell [14K]

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about the second one... well, is a "fait accompli" that using the pythagorean theorem, if x = 8 and y = 5, the hypotenuse must be √(8² + 5²) = √(89), which is neither of those choices.

5, 8, 13 are no dice, namely 5² + 8² ≠ 13

25, 64, 17 is are no dice too, because 25² + 17² ≠ 64²

however, 5,12 and 13 are indeed a pythagorean triple

also is 39, 80, 89.

when looking for a pythagorean triple, recall that c² = a² + b².

so the longest leg is the sum of the square of the small ones.

so what you'd do is, check the small legs, square them, add them up, if they're indeed a pythagorean triple, they "must" add up to the longest leg.

4 0
4 years ago
A kangaroo hops 2 kilometers in 4 minutes. How far can the Kangaroo hop in 10 minutes?
Artyom0805 [142]

Answer:

5 km

Step-by-step explanation:

10/4 = 2.5

2 x 2.5 = 5

6 0
3 years ago
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Solve the following system of equations express your answers as an ordered pair in the format (a,b) with no spaces between the n
EleoNora [17]
Double the first equation: 4x+14y=-2 and subtract the second: 17y=17, so y=1. 2x=-7y-1=-7-1=-8, so x=-8/2=-4.
The answer is x=-4 and y=1.
4 0
3 years ago
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Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

  • J(2;5); K(1;1)

             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

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3 years ago
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