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Anettt [7]
3 years ago
12

Jan is 2/3 of Karyn's age. Jan's age 8 years ago is 2/5 of Katyn's age 4 yeats from now. Jan is how many younger than Karyn?

Mathematics
1 answer:
Elden [556K]3 years ago
8 0

Answer:

12 years younger.

Step-by-step explanation:

Let Jan's age be J and Karyn's age be K.

J= \frac{2}{3}  K

Jan's age 8 years ago is 2/5 of Karyn's age 4 yeaRs from now.

J-8 = \frac{2}{5} (K+4)

=> (\frac{2}{3} - \frac{2}{5} ) K = \frac{8}{5} + 8

=> 4K = 48 X 3

=> K= 36.

=> J= 24.

So Jan is 12 years younger.

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First, you want to do inverse operations

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3 0
4 years ago
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Two students solved the same multi-step equation. Which student is correct? Explain the error. Student A Student B 2x - 4(3x + 6
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Answer:

Student B is correct

Student A failed to distribute -4 and -6 when opening the brackets in the first step

Step-by-step explanation:

The solution Student A gave was:

2x - 4(3x + 6) = -6(2x + 1) - 4

2x - 12x + 6 = -12x + 1 - 4

-10x + 6 = -12x - 3

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The solution Student B gave was:

2x - 4(3x + 6) = -6(2x + 1) - 4

2x - 12x - 24 = -12x - 6 - 4

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Student B is correct.

Explanation of the error:

Student A failed to distribute -4 and -6 when opening the brackets in the first step.

That is,

2x - 4(3x + 6) = -6(2x + 1) - 4

To open this bracket, we will distribute, -4 and -6 so that we get

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Collecting like terms

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∴ 2x = 14

x = 14 / 2

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x = 7

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