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2 years ago

How to solve 5{2p-4(p+5)}=25

Mathematics

2 answers:

Gekata [30.6K]2 years ago

7 0

Answer:

$p = - \frac{25}{2} = - 12 \frac{1}{2} = - 12.5$

Step-by-step explanation:

$5(2p - 4(p + 5)) = 25$

$2p - 4(p + 5) = 5$

$2p - 4p - 20 = 5$

$- 2p - 20 = 5$

$- 2p = 5 + 20$

$- 2p = 25$

$\boxed{\green{p = - \frac{25}{2} = - 12 \frac{1}{2} = - 12.5}}$

Hitman42 [59]2 years ago

5 0

Answer:

this is the solution of your questions don't mind my handwriting because I write it fast ⏩

Step-by-step explanation:

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2 years ago

candy that costs 31 cents per pound is mixed with candy that costs 46 cents per pound to obtain 50 pounds of candy that costs 40

photoshop1234 [79]

The amount of each type of candy (in pounds) that are mixed for the considered condition is: 20 pounds of first type of candy and 30 pounds of second type of candy.

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You can represent the unknown amounts by the use of variables. Follow whatever the description is and convert it one by one mathematically. For example if it is asked to increase some item by 4 , then you can add 4 in that item to increase it by 4. If something is for example, doubled, then you can multiply that thing by 2 and so on methods can be used to convert description to mathematical expressions.

For this case, we can assume the separate weights of each type of candies to be represented by variables.

Let we have:

x = weight (in pounds) of first type of candy whose cost is 31 cents per pound.
y = weight (in pounds) of second type of candy whose cost is 46 cents per pound.

x pounds of first type of candy is mixed with y pounds of second candy.

The weight of the mixture = x + y = 50 pounds

The cost of the mixture = 40 cents per pound = $40 \times 50 = 2000$ cents

Cost of the mixture = cost of x pounds of first candy+ cost of y pounds of second candy = $31x + 46y$
Thus, we get $31x + 46y =2000$

Therefore, we got a system of two linear equations as:

$x +y = 50\\31x + 46y =2000$

From first equation, we get:

$x = 50 -y$

Substituting this value in second equation, we get:

$31(50-y) + 46y =2000\\1550 + 15y = 2000\\15y = 450\\\\y = 450/15 = 30$

Putting this value of y in equation for x, we get:

$x = 50-y = 50-30 = 20$

Thus, the amount of each type of candy (in pounds) that are mixed for the considered condition is: 20 pounds of first type of candy and 30 pounds of second type of candy.

Learn more about solving system of linear equations here:

brainly.com/question/13722693

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2 years ago

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Is x²-x divisible by 2?

bagirrra123 [75]

Answer:

Yes

Step-by-step explanation:

There are two cases: Case 1: x is even, so x can be modelled as a generic number 2n, where n is a positive integer. Clearly this product is divisible by two. ... Hence, it is safe to generalise that the term x²-x is divisible by 2 for any positive integer x.

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3 years ago

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Select Yes or No to state whether each data set is likely to be normally distributed.

kenny6666 [7]

we know that

Normal distribution:

The normal distribution is a very common continuous probability distribution

A probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean

now, we will check each options

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so, it is discrete in nature

so, this is not normal distribution

option-B:

we know that

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so, this is normal distribution

option-C:

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so, this is discrete in nature

so, this is not normal distribution

option-D:

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time can be decimal or number

so, this is continuous in nature

so, this is normal distribution

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3 years ago

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