Hey there!
We're going to write the equation for this line in slope-intercept form, y = mx+b, where m is the slope and b is the y-intercept. In order to write it in this form, as stated in the name, we need the slope and y-intercept. Since we have the slope given, we can use the points we have and set up that equation with the given slope to solve for b. We'll use the x and y values and throw them into the equation. We have:
-1 = 3/2(4) + b
-1 = 12/2 + b
-1 = 6 + 6
-6 = b
Now, since we have our slope and y-intercept, we can write our equation with these two values:
y = 3/2x - 6
Hope this helps!
<span>17 – (–8) – 9
= 17 + 8 - 9
= 25 - 9
= 16
answer is 16</span>
Let Q be the point (a, b). Since the midpoint of P (2, 3) and Q (a, b) is (4, 6), we have
(2 + a)/2 = 4
(3 + b)/2 = 6
Solve for a and b :
(2 + a)/2 = 4
2 + a = 8
a = 6
(3 + b)/2 = 6
3 + b = 12
b = 9
So the coordinates of Q are (6, 9).
You find the range by adding all the sides I think
