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Naily [24]
3 years ago
6

x f(x) 3.0 4.0 3.5 -0.2 4.0 -0.8 4.5 0.1 5.0 0.6 5.5 0.7 For the given table of values for a polynomial function, where must the

zeros of the function lie? A. between 3.0 and 3.5 and between 4.0 and 4.5 B. between 3.5 and 4.0 and between 4.0 and 4.5 C. between 4.0 and 4.5 and between 4.5 and 5.0 D. between 3 .5 and 4.0 and between 4.0 and 4.5 E. between 3 .5 and 4.0 and between 5.0 and 5.5

Mathematics
1 answer:
torisob [31]3 years ago
5 0

Answer:

A. between 3.0 and 3.5 and between 4.0 and 4.5

Step-by-step explanation:

The idea here is that if a function is continuous and you have points on opposite sides of the x-axis, then there must be a zero-crossing between those points. As the table and graph show, ...

... (3.0, 4.0) and (3.5, -0.2)

are points on opposite sides of the x-axis. So, there must be a zero crossing between x=3.0 and x=3.5.

Likewise, ...

... (4.0, -0.8) and (4.5, 0.1)

are points on opposite sides of the x-axis. So, there must be a zero-crossing between x=4.0 and x=4.5

The appropriate answer choice lists both of these possible zero crossings.

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Answer:

24.

Step-by-step explanation:

the diameter is twice the radius

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George is given two circles, circle O and circle X 1 as shown. If he wants to prove that the two circles are similar, what would
salantis [7]

Answer:

Step-by-step explanation:

Given: The radius of circle O is r, and the radius of circle X is r'.

To prove: Circle O is similar to circle X.

Proof: Move the center of the smaller circle onto the center of the largest circle. Translate the circle X by the vector XA onto circle O. The circles now have the same center.

A dilation is needed to increase the size of circle X to coincide with the circle O. A value which when multiplied by r' will create r.

The scale factor x to increase X:

⇒

A translation followed by a dilation with scale factor  will map one circle to the other, thus proving the given both circles similar.

Therefore, circle O is similar to circle X.

Step-by-step explanation:

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3 years ago
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How did you use similarity to find the areas and circumferences of circles? How are the radius and diameter of a circle related?
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Step-by-step explanation:

4 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv
ch4aika [34]

Answer:

Part 1) The function of the First graph is f(x)=(x-3)(x+1)

Part 2) The function of the Second graph is f(x)=-2(x-1)(x+3)

Part 3) The function of the Third graph is f(x)=0.5(x-6)(x+2)

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

f(x)=a(x-c)(x-d)

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

f(x)=a(x-3)(x+1)

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

-4=a(1-3)(1+1)

-4=a(-2)(2)

a=1

therefore

The function is equal to

f(x)=(x-3)(x+1)

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

f(x)=a(x-1)(x+3)

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

8=a(-1-1)(-1+3)

8=a(-2)(2)

a=-2

therefore

The function is equal to

f(x)=-2(x-1)(x+3)

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

f(x)=a(x-6)(x+2)

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

-8=a(2-6)(2+2)

-8=a(-4)(4)

a=0.5

therefore

The function is equal to

f(x)=0.5(x-6)(x+2)

3 0
3 years ago
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