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enyata [817]
3 years ago
14

A solid is 5 cm tall ,3 cm wide and 2cm thick what is it's density

Mathematics
1 answer:
Lostsunrise [7]3 years ago
3 0
Here's the work:
Density = mass/volume = 129g/(5*3*2) cm^3 = 4.3 g/cm^3.
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Which of the following could be points on the unit circle: A. (4/3, 4/5) B. (5/13, 12/13)
IRINA_888 [86]

Answer:

Option (2) and (4) are correct.

(\frac{5}{13},\frac{12}{13} ) and  (\frac{6}{7},\frac{\sqrt{13}}{7} ) are points on the unit circle.

Step-by-step explanation:

Given : Some points of circles.

We have to choose which points could be points on the unit circle.

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2) (\frac{5}{13},\frac{12}{13} )

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(\frac{5}{13})^2+(\frac{12}{13})^2

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Put  in LHS of  (1) , we have,

(\frac{1}{3})^2+(\frac{2}{3})^2

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Put  in LHS of  (1) , we have,

(\frac{6}{7})^2+(\frac{\sqrt{13}}{7})^2

Simplify, we have,

=\frac{36}{49}+\frac{13}{49}

=\frac{49}{49}= 1

Thus,  (\frac{6}{7},\frac{\sqrt{13}}{7} ) is a point on the unit circle.

Thus, (\frac{5}{13},\frac{12}{13} ) and  (\frac{6}{7},\frac{\sqrt{13}}{7} ) are points on the unit circle.

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