Answer:
b=a √3
Step-by-step explanation:
Okay, first, given the equation, we need to find out what the radius of the circle is. Let us state the general equation of a circle:

Where

is the centre of the circle. In this case, we don't need to know the centre. Just the radius.
Let us start by converting the equation into standard for, which I typed above. Divide both sides by 81.

Great! We now know the radius of the circle. It is

because it is the bottom fraction. Now we know that the radius is 9.
So now lets input this into the area of circle formula:
Now we insert our radius.
You can convert that into a decimal if you wish.
Hope this helped!
~Cam943, Moderator
Answer: C. No solution. ( top shaded. Middle not. Bottom shaded.
Step-by-step explanation:
Given inequalities
y< -1/3x+5 and
y> -1/3x-1.
If we draw graph for y< -1/3x+5 equation, it would be a dotted line and we would shade down the dotted line because we have less than < symbol there.
Now, if we draw graph for second inequality y> -1/3x-1, it would also be a dotted line and we would shade up of dotted line because we have greater than > symbol there.
Now, we can see that slopes of both dotted lines are same that is -1/3.
So, there would not be any common shaded region.
Therefore, there would not by any solution of the system of inequalities.
And correct option is C option.
C. No solution. ( top shaded. Middle not. Bottom shaded.
Answer:
24%
Step-by-step explanation:
50 is the 100%
so
12/50= 24%
Answer:
Alternative C is the correct answer
Step-by-step explanation:
The first step is to determine the composite function;
![f[g(x)]](https://tex.z-dn.net/?f=f%5Bg%28x%29%5D)
![f[g(x)]=cos[cot(x)]](https://tex.z-dn.net/?f=f%5Bg%28x%29%5D%3Dcos%5Bcot%28x%29%5D)
We then employ a graphing utility to determine the range and the domain of the new function.
The range is the set of y-values for which the function is defined. In this case it is;
![[-1,1]](https://tex.z-dn.net/?f=%5B-1%2C1%5D)
On the other hand, the domain refers to the set of the x-values for which the function is real and defined. In this case; it is the set of real numbers x except x does not equal npi for all integers n.