X=-5 is your answer. Hope this helps :)
Answer:
at 2/3 seconds
Step-by-step explanation:
S1(t) = t³ + 2
Average speed, dS1/dt = 3t²
S2(t) = t²
Average speed, dS2/dt = 2t
The distance between the objects is
dS1/dt - dS2/dt
= 3t² - 2t
The time the distance between the two object is at minimum is when the distance is 0
That is, when
3t² - 2t = 0
t(3t - 2) = 0
t = 0 or 3t - 2 = 0
t = 0 or t = 2/3
5<em>x</em>² - 7<em>x</em> + 2 = 0
5(<em>x</em>² - 7/5 <em>x</em>) + 2 = 0
5(<em>x</em>² - 7/5 <em>x</em> + 49/100 - 49/100) + 2 = 0
5(<em>x</em>² - 2 • 7/10 <em>x</em> + (7/10)²) - 49/20 + 2 = 0
5(<em>x</em> - 7/10)² - 9/20 = 0
5(<em>x</em> - 7/10)² = 9/20
(<em>x</em> - 7/10)² = 9/100
<em>x</em> - 7/10 = ± √(9/100)
<em>x</em> - 7/10 = ± 3/10
<em>x</em> = 7/10 ± 3/10
<em>x</em> = 10/10 = 1 or <em>x</em> = 4/10 = 2/5
Answer:
u=0.375
Step-by-step explanation:
First we can write the equation down, -6(-4u+4)-6u=2(u-5)-8. First what you want to do is distribute -6 to (4u+4) and 2 to (u-5). This would result in 24u-24-6u=2u-10-8. Next add up all like terms and you will get 18u-24=2u-18. Next you would want to add 24 on both sides so that you get 18u=2u+6 then subtract 2u from both sides to get 16u=6. You the divide 16 on both sides to get u=0.375.
Equate real part and imaginary part:
LHS:
real part -- 12
imaginary part -- 5y
RHS:
real part = 4x
imaginary part = 25
Equating::
12 = 4x
x = 12/4
x = 3
Again:
5y = 25
y = 25/5
y = 5
So,
x = 3
y = 5
