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3 years ago

Write a slope-intercept equation of the line that passes through the points (4,11) and (6,8).

Mathematics

1 answer:

grin007 [14]3 years ago

5 0

Answer:

y= $\frac{3}{-2}$ x +17

Step-by-step explanation:

$\frac{11-8}{4-6}$ = $\frac{3}{-2}$ =slope

11= $\frac{3}{-2}$ *4 + C

11=-6 + C

17=C=Y-intercept

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Zina [86]

Answer:

0.0208<p<0.0592

Step-by-step explanation:

-Given the sample size is 400 and the desired proportion is 16.

-The confidence interval can be determined as follows:

$CI=\hat p\pm z\sqrt{\frac{\hat p(1-\hat p}{n}}\\\\\hat p=x/n=16/400=0.04$

#We the use this proportion to find the CI at 95%:

$CI=0.04\pm 1.96\times \sqrt{\frac{0.04(1-0.04)}{400}}\\\\=0.04\pm 0.0192\\\\=[0.0208,0.0592]$

Hence, the 95% confidence interval is 0.0208<p<0.0592

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3 years ago

CAN SOMEONE JUST ANSWER THIS QUESTION

kramer

Answer:

1/5

Step-by-step explanation:

There are 3 numbers of less than 4 (1, 2 and 3) and there are 2 multiples of 9 (9 and 18). So there are 5 favourable outcomes and 25 possible outcomes. So you put 5/25 and cancel down, which makes 1/5. I hope this helps!

6 0

3 years ago

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What is the value of the expression 2[4(2^3+5)]-4^2

ivolga24 [154]

Answer:

Step-by-step explanation:

Solve inside first

2^3=8

8+5= 13

Now multiply by 4

=52

Now by 2

=104

Now this is what we have left

=104-4^2

Make it easy by solving 4^2 which is 16.

104-16

=88

3 0

3 years ago

supervisor records the repair cost for 25 randomly selected dryers. A sample mean of $93.36 and standard deviation of $19.95 are

Simora [160]

<h2><u>Answer with explanation:</u></h2>

The confidence interval for population mean (when population standard deviation is unknown) is given by :-

$\overline{x}-t^*\dfrac{s}{\sqrt{n}}< \mu$

, where n= sample size

$\overline{x}$ = Sample mean

s= sample size

t* = Critical value.

Given : n= 25

Degree of freedom : $df=n-1=24$

$\overline{x}= \$93.36$

$s=\ $19.95$

Significance level for 98% confidence interval : $\alpha=1-0.98=0.02$

Using t-distribution table ,

Two-tailed critical value for 98% confidence interval :

$t^*=t_{\alpha/2,\ df}=t_{0.01,\ 24}=2.4922$

⇒ The critical value that should be used in constructing the confidence interval = 2.4922

Then, the 95% confidence interval would be :-

$93.36-(2.4922)\dfrac{19.95}{\sqrt{25}}< \mu$

$=93.36-9.943878< \mu$

$=83.416122< \mu$

Hence, the 98% confidence interval for the mean repair cost for the dryers. = $83.4161$

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3 years ago

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Nat2105 [25]

Answer:

where is the question????

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3 years ago

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