Y= 6(1.013) x x+ 110

Mathematics

1 answer:

Sveta_85 [38]2 years ago

5 0

If u tell me what operation<span> is in between both the x's, then i can solve it for you</span>

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Write each number in standard form 6.7x10 to the 1 power

e-lub [12.9K]

<h2>Answer: 67</h2>

Step-by-step explanation: 6.7 x 10^1 = 67

8 0

2 years ago

A picnic basket was marked up 95% from an original cost of $9.57. Last Friday, Rosanne bought the picnic basket and paid an addi

Montano1993 [528]

Answer:

$20.15

Step-by-step explanation:

Given data

Original cost = $9.57

Markup= 95%

Let us find the new cost of the basket

=95/100*9.57

=0.95*9.57

=$9.0915

Hence the cost of the basket is

= 9.57+9.0915

=18.66

Also, the sales tax is 8%

=8/100*18.66

=0.08*18.66

=1.4928

Therefore, the total amount to be paid is

=18.66+1.4928

=$20.15

8 0

2 years ago

Prove that the diagonals of a parallelogram bisect each other

Nady [450]

Answer:

[ See the attached picture ]

The diagonals of a parallelogram bisect each other.

✧ Given : ABCD is a parallelogram. Diagonals AC and BD intersect at O.

✺ To prove : AC and BD bisect each other at O , i.e AO = OC and BO = OD.

Proof : $\begin{array}{ |c| c | c | } \hline \tt{SN}& \tt{STATEMENTS} & \tt{REASONS}\\ \hline 1& \sf{In \: \triangle ^{s} \:AOB \: and \: COD } \\ \sf{(i)}& \sf{ \angle \: OAB = \angle \: OCD\: (A)}& \sf{AB \parallel \: DC \: and \: alternate \: angles} \\ \sf{(ii)} &\sf{AB = DC(S)}& \sf{Opposite \: sides \: of \: a \: parallelogram} \\ \sf{(iii)} &\sf{ \angle \: OBA= \angle \: ODC(A)} &\sf{AB \parallel \:DC \: and \: alternate \: angles} \\ \sf{(iv)}& \sf{ \triangle \:AOB\cong \triangle \: COD}& \sf{A.S.A \: axiom}\\ \hline 2.& \sf{AO = OC \: and \: BO = OD}& \sf{Corresponding \: sides \: of \: congruent \: triangle}\\ \hline 3.& \sf{AC \: and \: BD \: bisect \: each \: other \: at \: O}& \sf{From \: statement \: (2)}\\ \\ \hline\end{array}. Proved ✔$

♕ And we're done! Hurrayyy! ;)

# STUDY HARD! So, Tomorrow you can answer people like this , " Dude , I just bought this expensive mobile phone but it is not that expensive for me" [ - Unknown ] :P

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