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photoshop1234 [79]
3 years ago
6

Y= 6(1.013) x x+ 110

Mathematics
1 answer:
Sveta_85 [38]3 years ago
5 0
If u tell me what operation<span> is in between both the x's, then i can solve it for you</span>
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There are 35 female performers in a dance recital. The ratio of men to women in the recital is 2 : 7 How many men are in the rec
Vsevolod [243]

There are 32 female performers in a dance recital the ratio of men to women is 3/8 How many men are in the dance recital

But we have 32 female performers in the dance recital. Hence there are 3×4=12 men in the dance recital.

3 0
3 years ago
Get brainliest SOlve correctly
Minchanka [31]

download the thing below

Download pdf
8 0
3 years ago
Read 2 more answers
Please Hurry) What is the length of side AC of the triangle? □ units. ​
NARA [144]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

\boxed{\mathrm{AC = 25 \:\: units ~}}

\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}

As we can see in the given figure, Angles A and B are equal. therefore their opposite sides will be equal to one another, that is ~

  • AB = BC

now, let's plug the values of AB and BC in terms of x and equate them to find the value of x ~

  • 5x + 5 = 7x - 1

  • 7x - 5x  = 5 + 1

  • 2x = 6

  • x = 6 \div 2

  • x = 3 \:  \: units

now , let's find the measure of side AC ~

  • AC = 6x + 7

that is ~

  • 6(3) + 7

  • 18 + 7

  • 25 \:  \: units

8 0
2 years ago
Cheryl collected data for her mathematics project. She noted that the data set was approximately normal.
nadya68 [22]

Answer:

X_(r) >> X_(n)

The mean for this case would increase since is defined as:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

The interquartile range would not change since the definition for the IQR is IQR =Q_3 -Q_1 and the quartiles are the same.

The standard deviation would not remain the same since by definition is:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And since we change the largest value the deviation would increase considerably.

And for the last option is not always true since if we select a value so much higher then the distribution would be skewed to the right.

So the best option for this case is:

Mean would increase.

Step-by-step explanation:

For this case we assume that we have a random sample given X_(1), X_(2) ,..., X_(n) and for each observation X_i \sim N(\mu, \sigma) since the problem states that the data is approximately normal.

Let's assume that the largest value on this sample is X_(n) and for this case we are going to replace this value by another one extremely higher so we satisfy this condition:

X_(r) >> X_(n)

The mean for this case would increase since is defined as:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

The interquartile range would not change since the definition for the IQR is IQR =Q_3 -Q_1 and the quartiles are the same.

The standard deviation would not remain the same since by definition is:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And since we change the largest value the deviation would increase considerably.

And for the last option is not always true since if we select a value so much higher then the distribution would be skewed to the right.

So the best option for this case is:

Mean would increase.

6 0
3 years ago
Sam has 3/4 ton of stones to divide evenly among for sidewalks. how much stone will it be used in each sidewalk
mel-nik [20]

The amount of stone in each sidewalk is 3/16

<h3>How to determine the amount of stone in each sidewalk?</h3>

The given parameters are

Stones = 3/4 tons

Side walks = 4

The amount of stone in each sidewalk is calculated using

Amount = Stones/Side walks

Substitute the known values in the above equation

Amount = 3/4 / 4

Evaluate the quotient

Amount = 3/16

Hence, the amount of stone in each sidewalk is 3/16

Read more about proportions at:

brainly.com/question/1781657

#SPJ1

7 0
1 year ago
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