We are asked to define the width and length of a rectangular college athletic field with a parameter of 98 and length 12 more than the width, we represent x as the width, that is the length is x+12. Using parameter formula: 96/2 = x + x+ 12 ; <span>48 = 2x + 12; x is equal to 18 m while x + 12 is equal to 30 m </span>
Answer:
since the total amount of wire is not given, I looked for a similar question:
- you have 800 yards of wire at your disposal
since we need to only calculate 3 sides of the land plot, our perimeter will be:
L + 2W = 800
area = L x W
L = 800 - 2W
now we replace:
area = (800 - 2W) x W = 800W - W²
we can write a quadratic equation:
area = -W² + 800W
the vertix of W = -b/2a
the coefficients of our quadratic equation are: -2 and 8
the vertix of W = -800 / (2 x -2) = -800 / -4 = 200 yards
width = 200 yards
length = 800 - (200 x 2) = 400 yards
maximum area enclosed = 200 x 400 = 80,000 sq yards
<span>The bisector of an angle is a ray whose end point is the vertex of the angle where it divides the angle into two smaller congruent angles. Therefore, it is in the interior of an angle and it shares a side.
</span>B.
<span>contains the vertex of the angle</span>
Answer:
A. 6.25x + 7.50 = 26.25
Step-by-step explanation:
Clara paid 7.50 for an admission ticket, each round was 6.25 and she did it for x rounds. 6.25x is the same thing as 6.25 times x rounds.
I’m pretty sure the answer is C
