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Likurg_2 [28]
2 years ago
14

The student body of a large university consists of 60% female students. A random sample of 8 students is selected. Refer to Exhi

bit 5-8. What is the probability that among the students in the sample at least 6 are male?
Mathematics
1 answer:
jasenka [17]2 years ago
8 0

Answer:

0.0499

Step-by-step explanation:

This is a binomial probability  function expressed as:

P(X=x)={n\choose x}p^x(1-p)^{n-x}\\\\

Given that n =8, and p(male)=1-0.6=0.4, the probability of at least 6 being male is calculated as:

P(X=x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X\geq 6)=P(X=6)+P(X=7)+P(X=8)\\\\={8\choose 6}0.4^6(0.6)^{2}+{8\choose 7}0.4^7(0.6)^{1}+{8\choose 8}0.4^8(0.6)^{0}\\\\=0.0413+0.0079+0.0007\\\\=0.0499

Hence, the probability of at least 6 males is 0.0499

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Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed.
OLEGan [10]

Answer: the value of population standard deviation is 3.87

Step-by-step explanation:

From the information given,

Number of sample, n = 8

For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.

We will apply the formula

Confidence interval

= mean ± z ×standard deviation/√n

Since confidence interval = 2.694,

It becomes

2.694 = 1.96 × standard deviation/√8

Dividing both sides of the equation by 1.96, it becomes

1.37 = standard deviation/√8

Standard deviation = 1.37 × √8

Standard deviation = 3.87

3 0
3 years ago
A car travels the first 50km of its journey at an average speed of 25m/s snd the next 120km at an average speed of 80km/h. The c
Alex17521 [72]

Answer:

84,6km/h

Step-by-step explanation:

the whole journey was

in the first part the car travels 50km, in the second part 120km and in the third part we can find it with a simple rule of three

90km--->60 min

X<--------35min= 52.5 km the car made in the last part

50km+120km+52,5km=222.5km was all the journey

and he made it in:

  • the last part in 35min,
  • in the second part we know that the car was going at 80km/h and that he made 120km so:

80km--->60 min

120km--->90 min

  • in the first part we know that the car was going at 25m/s and he made 50km. 25m/s*1km/1000m*3600s/1h= we obtain the speed in km/h=90km/h

90km---->60min

50km---->x=33,333 min

The whole journey last 33,333min+90min+35min=158.333min

if we express that in hour = 158.333min*1hr/60min=2.63

the car made 222.5km in 2.63 hour

so the average speed was

222.5---->2.63hr

X--------1hr=84,6

the average speed was 84,6km/h

5 0
3 years ago
Using sq root property. 2x^2+36+0
mezya [45]
It’s 2.&:&/8/8/8&/keisjsisk
5 0
3 years ago
How many centimeters are in 7 meters 100cm/1m=?/7m
Nikitich [7]
It there are 100 centimeters in 1 meter, then there are 700 centimeters in 7 meters. :)
6 0
2 years ago
Please help and explain why so i understand it please
Daniel [21]
That question probably meant how far are the two distances.

One way to solve this problem is by using the distance formula which you can search up.

and so the answer is d=13. D is distance
3 0
2 years ago
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