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Aleksandr-060686 [28]
3 years ago
8

Evaluate the expression if m = −4, n = 1, p = 2, q = −6, r = 5, and t = −2.

Mathematics
2 answers:
Step2247 [10]3 years ago
8 0
I hope you understood!! :)

suter [353]3 years ago
6 0
16+4(3q+p)
=16+4[3(-6)+2]
=16+4[-18+2]
=16+4[-16]
=16-64
= -48
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X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?
cluponka [151]

Answer:

x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

Step-by-step explanation:

I'm assuming the system is \left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.:

x^2+y^2=2

x^2+(2x^2-3)^2=2

x^2+(4x^4-12x^2+9)=2

x^2+4x^4-12x^2+9=2

4x^4-11x^2+9=2

4x^4-11x^2+7=0

x^4-11x^2+28=0

(x^2-7)(x^2-4)=0

(4x^2-7)(x^2-1)=0

4x^2-7=0

4x^2=7

x^2=\frac{7}{4}

x=\pm\sqrt{\frac{7}{4}}

x^2-1=0

x^2=1

x=\pm1

y=2x^2-3

y=2(\pm\sqrt{\frac{7}{4}})^2-3

y=2({\frac{7}{4}})-3

y=\frac{7}{2}-3

y=\frac{1}{2}

y=2x^2-3

y=2(\pm1)^2-3

y=2(1)-3

y=2-3

y=-1

Therefore, x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

4 0
2 years ago
What is the square root of 98/2
timurjin [86]

Answer:

7

Step-by-step explanation:

\sqrt{ \frac{98}{2} }  =  \sqrt{49 }  = 7

I hope it helped you

8 0
2 years ago
Which system type is a linear system with infinitely many solutions?
Maru [420]

Answer: C

Step by step explanation-

4 0
3 years ago
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Drag the numbers to order them from greatest to least, with the greatest at the top.
astraxan [27]

Step-by-step explanation:

5.03709

4.923935

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4 0
2 years ago
Can someone help me solv for x?
Alexxx [7]

Answer:

AB=AC

X²+8 =33

X²=33-8

X²=25.

X=√25

X=5

5 0
3 years ago
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