Question

At the city museum, child admission is $5.20 and adult admission is $9.50. On Friday,133 tickets were sold for a total sales of $928.10. How many adult tickets were sold that day?

Answer 1

Answer:

55 adult tickets were sold on Friday.

Step-by-step explanation:

A linear system will be used to model the system.

Let c be the number of child tickets and a be the number of adult tickets

Then according to given statements

$a+c = 133\ \ \ \ Eqn\ 1\\9.50a+5.20c = 928.10\ \ \ Eqn\ 2$

From equation 1

$a = 133-c$

Putting this in equation 2

$9.50(133-c)+5.20c = 928.10\\1263.5-9.50c+5.20c=928.10\\1263.5-4.3c = 928.10\\-4.3c = 928.10-1263.5\\-4.3c=-335.4\\\frac{-4.3c}{-4.3} = \frac{-335.4}{-4.3}\\c = 78$

Putting c = 78 in equation 1

$a+78 = 133\\a = 133-78\\a = 55$

Hence,

55 adult tickets were sold on Friday.