A cannonball is fired in the air at an Angel of 45 degree. How far does it travel before it is 900 feet above ground.
1 answer:
Answer:
900√2 or 1272.79 ft.
Step-by-step explanation:
Imagine this cannonball making a triangle. When it reaches 900 feet, it will make a straight line down to the ground, making a leg. The imaginary line and ground make up the legs of the triangle with a 90° angle.
We can use the 45-45-90 triangle method
This means the hypotenuse is √2 times the length of a leg
900 x √2 = 1272.79221
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