Answer:
I assume you know Arithmetic Progression .
so, we have to find the first and last 4-digit number divisible by 5
first = 1000 , last = 9990
we have a formula, 
= a + (n-1)d
here, is the last 4-digit number divisible by 5.
n is the number of 4-digit even numbers divisible by 5
d is the common difference between the numbers, which is 10 in this case
a is the first 4-digit number divisible by 5
9990 = 1000 + (n-1)*10
899 = n-1
n = 900
Hence, there are 900 4-digit even numbers divisible by 5
Answer:
6 bags
Step-by-step explanation:
The first gift is a box of 18 chocolate candy bars, and the second gift is a pack of 12 cookies. Destiny wants to use all of the chocolate candy bars and cookies to make identical snack bags for her cousins. What is the greatest number of snack bags that Destiny can make? Answer: 6 bags
The First group i.e 1-10 include more prime numbers .(2,3,5,7,1)
- Because it has the basic inputs of every number
- Like 15 consists of 3×5
18-4.25=13.75$ she has. 13.75-9.75=4$ she can spend. 4$/0.50=8 packages she can buy
Please mark Brainliest. Plz.
Answer:
x^2 = 25 x = 5, -5
2x^2 = 98 x = 7, -7
x^2 + 64 = 0 x = 8i, -8i
9x^2 - 16 = 0 x = 4/3, -4/3
x^2 + 9 = 25 x = 4, -4
(x-2)^2 = 25 x = 7, -3
(x-2)^2 +9 = 25 x = 6, -2
4(x-2)^2 +9 = 25 x = 4, 0
