Answer:
The position P is:
ft <u><em> Remember that the position is a vector. Observe the attached image</em></u>
Step-by-step explanation:
The equation that describes the height as a function of time of an object that moves in a parabolic trajectory with an initial velocity 
is:
Where 
is the initial height = 0 for this case
We know that the initial velocity is:
82 ft/sec at an angle of 58 ° with respect to the ground.
So:
ft/sec
ft/sec
Thus
The height after 2 sec is:
Then the equation that describes the horizontal position of the ball is
Where
for this case
ft / sec
ft/sec
So
After 2 seconds the horizontal distance reached by the ball is:
Finally the vector position P is:
ft
Use pythagorean’s theorem
as you can see it’s a right isosceles triangle
so your equation is adapted to this:
p^2 + p^2=44^2
add like terms and simplify
2p^2=1936
divide by 2
p^2=968
square root
p= √968
simplify
p=22√2
the answer would be your second option
Answer:
y = [4(x-3)]/3
Step-by-step explanation:
4x = 12+3y
3y = 4x-12
y = [4(x-3)]/3
Best regards
You have to round it to the nearest hundreds
.01 is the answer to that or one one hundredth
