The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
Distance traveled by car A =x, (when the car B is at the same distance from the start line)
time of car A=t
x=10 m/st ⇒ x=10t (1)
Distance traveled by car B=x
time of car B=t-3
x=15(t-3) (2)
With the equations (1) and (2) we make a system of equations:
x=10t
x=15(t-3)
We solve this system of equations:
10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9
t-3=9-3=6
x=10 t=10 (9)=90
Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
Answer:
A. x=16
Step-by-step explanation:
Similar triangles/ratios
1. Substitute 2x + 7 = 39, 4x + 1 = 65
2. Find size ratio between the two figures, 5:3
3. Check for similarity - 39 x 5/3 = 65
Answer:
Step-by-step explanation: ifk
Answer:
B
Step-by-step explanation:
We subtract 4 from each side to get 
Let's plug in a random point such as 0.
Since this is true, the inequality we made is true.
