You divide both sides by 14:

Answer:
I think its 9 to 45, b.
Step-by-step explanation:
because the a gets you a 39900% , and c gets you a 500%, and d gets you a 300%. So b is the only option that makes sense.
Answer: -13.9
This value is approximate.
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Explanation:
This angle is in quadrant Q2, which is where x is negative and y is positive.
The angle shown of 65 degrees is added to the 90 degree angle to the right resulting in 65+90 = 155 degrees overall. See diagram below.
The x component of the vector is found by the formula
x = r*cos(theta)
we will plug in r = 15.3 as the magnitude of the vector and theta = 155 as the angle
x = 15.3*cos(155)
x = -13.8665 approximately
x = -13.9 rounding to one decimal place (as 15.3 and 65.0 are both rounded to one decimal place)
Answer:
where −5 ≤ x ≤ 3
Step-by-step explanation:
The given function is
.
We want to select the option that describes all the solutions to the parabola.
The domain of the parabola is −5 ≤ x ≤ 3.
This means that any x=a on −5 ≤ x ≤ 3 that satisfies (a,f(a)), is a solution.
This can be rewritten as 
Therefore for x belonging to −5 ≤ x ≤ 3, all solutions are given by:
where −5 ≤ x ≤ 3.
Answer:
Step-by-step explanation:
The desired formula parameters for Newton's Law of Cooling can be found from the given data. Then the completed formula can be used to find the temperature at the specified time.
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<h3>Given:</h3>

<h3>Find:</h3>
k
T(4)
<h3>Solution:</h3>
Filling in the given numbers, we have ...
185 = 68 +(208 -68)e^(-k·3)
117/140 = e^(-3k) . . . . . subtract 68, divide by 140
ln(117/140) = -3k . . . . . . take natural logarithms
k = ln(117/140)/-3 ≈ 0.060
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The temperature after 4 minutes is about ...
T(4) = 68 +140e^(-0.060·4) ≈ 68 +140·0.787186
T(4) ≈ 178.205
After 4 minutes, the final temperature is about 178 °F.