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2 years ago

A medical company tested a new drug for possible side effects. The table

Mathematics

2 answers:

Anna007 [38]2 years ago

6 0

Answer:

The answer is A.

Step-by-step explanation:

While they don't give nearly enough information on sampling size to be credible data or how many kids vs how many adults, the simplistic answer is (A) a greater percentage of kids experienced side effects among their peers than the adults among their peers.

tangare [24]2 years ago

6 0

Answer:

yes. A greater percentage of adults experienced side effects than children

Step-by-step explanation:

just did it

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When solving an equation, Carmen's first step is shown below. Which property justifies Carmen's first step? plz help me

Damm [24]

Answer:

the addition property of equality

Step-by-step explanation:E

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2 years ago

(8x+5)+(−x2−8) I don't know what to do

nexus9112 [7]

Answer：

$-x^{2} +8x-3$

Step-by-step explanation:

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2 years ago

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pogonyaev

Y-1=2(x+3) just plug into the formula

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2 years ago

How do u regroup when u find the sum of 64+43

Anarel [89]

What we are going to do is use the DISTRIBUTIVE PROPERTY. This distributive the numbers, to make it easier to solve.

So we will break 64 up.

64 = 60 + 4

43 = 40 + 3

60 + 40 = 100

4 + 3 = 7

100 + 7 = 107

So, 64 + 43 = 107.

Hope I helped ya!!!!!!!

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2 years ago

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The angle θ 1 is located in Quadrant IV, and cos ⁡ ( θ 1 ) = 9/ 19 , theta, start subscript, 1, end subscript, right parenthesis

Firdavs [7]

Answer:

$sin\theta_1 = - \frac{2\sqrt{70}}{19}$

Step-by-step explanation:

We are given that $\theta_1$ is in fourth quadrant.

$cos\theta_1$ is always positive in 4th quadrant and

$sin\theta_1$ is always negative in 4th quadrant.

Also, we know the following identity about $sin\theta$ and $cos\theta$ :

$sin^2\theta + cos^2\theta = 1$

Using \theta_1 in place of \theta:

$sin^2\theta_1 + cos^2\theta_1 = 1$

We are given that $cos\theta_1 = \frac{9}{19}$

$\Rightarrow sin^2\theta_1 + \dfrac{9^2}{19^2} = 1\\\Rightarrow sin^2\theta_1 = 1 - \dfrac{81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{280}{361}\\\Rightarrow sin\theta_1 = \sqrt{\dfrac{280}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{2\sqrt{70}}{19}, -\dfrac{2\sqrt{70}}{19}$

$\theta_1$ is in 4th quadrant so $sin\theta_1$ is negative.

So, value of $sin\theta_1 = - \frac{2\sqrt{70}}{19}$

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2 years ago