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Studentka2010 [4]
2 years ago
9

Simplify the expression. 10 (n^2+ n) - 6 (n^2 - 2)

Mathematics
1 answer:
Gnom [1K]2 years ago
3 0
<h3>10(n²+n)-6(n²+2)</h3><h3>10n²+10n-6n²-12</h3><h3>10n²-6n²+10n-12</h3><h3>4n²+10n-12</h3>

please mark this answer as brainlist

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If two marbles are randomly selected from the bag without replacement, what is the probability that the first marble is blue?
joja [24]

Answer:1,0.5, or 0 it depends

Explanation:

The probability that one event occurred depends on the total of random event, being 1 the most of the probabilities

If the two marbles are blue the probability to select a marble blue is 1

If one of the marbles is blue and the other marble is of any color the probability to select the blue marbles is:

P=1 - 1/2=1/2

Being 1/2 or 0.5 the answer

If any of the marbles are blue then the probabilities are 0

8 0
3 years ago
Multiply the trinomial x^2+xy+y^2 times the binomial x-y and simplify.
Natalija [7]
Multiply then simplify, that's doing the same work twice...anyway

x^3+x^2y+xy^2-x^2y-xy^2-y^3

x^3-y^3  which if factored is:

(x-y)(x^2+xy+y^2)  which is what you started with :)
6 0
3 years ago
Identify the vertex, axis of symmetry, minimum or maximum, domain, and range of the function f(
alekssr [168]

Identify the vertex, axis of symmetry, minimum or maximum, domain, and range of the function ()=−(+)^−

<em><u>Answer:</u></em>

vertex = (-4, -5)

Axis of symmetry = -4

use the (-4, -5) to find the minimum value

Domain = ( - \infty, \infty ) , [ x | x\ is\ real ]\\\\Range = [ -5, \infty ), y\geq -5

<em><u>Solution:</u></em>

Given function is:

f(x) = (x+4)^2 - 5

The equation in vertex form is given as:

y = a(x-h)^2+k

Where, (h, k) is constant

On comparing give function with vertex form,

h = -4

k = -5

Vertex is (-4 , -5)

Axis of symmetry : x co-ordinate of vertex

Thus, axis of symmetry = -4

The coefficient of x^2 is positive in given function.

Thus the vertex point will be a minimum

Minimum\ value = f(\frac{-b}{a})

f(x) = x^2 + 8x + 16 - 5\\\\f(x) = x^2 + 8x + 11

f(x) = ax^2+bx+c

On comparing,

a = 1

b = 8

x = \frac{-b}{2a} = \frac{-8}{2 \times 1} = -4

f(-4) = (-4)^2 + 8(-4) + 11 = 16 - 32 + 11 = -5

Thus, use the (-4, -5) to find the minimum value

Domain and range

f(x) = (x+4)^2 - 5

The domain is the input values shown on the x-axis

The range is the set of possible output values f(x)

Therefore,

Domain = ( - \infty, \infty ) , [ x | x\ is\ real ]\\\\Range = [ -5, \infty ), y\geq -5

4 0
3 years ago
Help if possible, thanks.
lukranit [14]

Answer:

1,2,3,6 are congruent

Step-by-step explanation:

4 0
3 years ago
AHHHHHHHHH help me eddd​
vaieri [72.5K]

Answer:

you add your number and then you subtract it so all the other steps are are going to be the exact same

5 0
3 years ago
Read 2 more answers
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