Pls help with question 6 someone!! It’s hard

Mathematics

1 answer:

boyakko [2]3 years ago

4 0

Answer:

6) AC could equal BD if ABCD were a square OR ABCD could be a rectangle.

7) I can't read all of #7

Step-by-step explanation:

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koban [17]

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3 years ago

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den301095 [7]

Step-by-step explanation:

$(\frac{8.4.2}{8.7} )^{2} \times (\frac{ {8}^{0} }{{7}^{ - 3} } )^{3 } \times {7}^{ - 9} \\ \\ = (\frac{8}{7} )^{2} \times (\frac{ 1}{{7}^{ - 3} } )^{3 } \times {7}^{ - 9}..... (\because a^0=1)\\ \\ = \frac{64}{49} \times ({{7}^{ 3} } )^{3 } \times {7}^{ - 9} \\ \\ = \frac{64}{49} \times {{7}^{ 3 \times 3} } \times {7}^{ - 9} \\ \\ = \frac{64}{49} \times {{7}^{ 9} } \times {7}^{ - 9} \\ \\ = \frac{64}{49} \times {{7}^{ 9 - 9} } \\ \\ =\frac{64}{49} \times {{7}^{ 0} } \\ \\ =\frac{64}{49} \times 1 \\ \\ = \frac{64}{49}$