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alukav5142 [94]
3 years ago
7

What is 4=2x as a improper fraction or integer

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
3 0

Answer:

2/4 or 1/2

Step-by-step explanation:

Divide both sides by 2 and you get x=2/4. You can simplify further by dividing 2 and 4 by 2 to get 1/2

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Dilate the figure by the scale factor. Then enter
Rzqust [24]

Answer:

there you go but im not sure . hope its helpful and good luck ;)

7 0
3 years ago
Somebody please help me with this geometry work
dimulka [17.4K]

Answer:

m∠EGF = 65°  and m∠CGF = 115°

Step-by-step explanation:

Given;

∠EFG = 50°

EF = FG

Solution,

In ΔEFG m∠EFG = 50° and EF = FG.

Since triangle is an isosceles triangle hence their base angles are always equal.

∴m\angle FEG = m\angle EGF

Let the measure of ∠EGF  be x.

∴ m\angle FEG = m\angle EGF = x

Now by angle Sum property which states "The sum of all the angles of a triangle is 180°."

m∠EFG + m∠FEG + ∠EGF = 180

50\°+x+x=180\°\\50\°+2x=180\°\\2x= 180\°-50\°\\2x=130\°\\x=\frac{130}{2}= 65\°

Hence

m∠EGF = 65°  

Also 'The sum of angles that are formed on a straight line is equal to 180°."

m∠EGF + m∠CGF = 180°

65° + m∠CGF = 180°

m∠CGF = 180° - 65° = 115°

Hence m∠EGF = 65°  m∠CGF = 115°

8 0
3 years ago
A small publishing company is planning to publish a new book. The production costs will include one-time fixed costs (such as ed
drek231 [11]
21499 +12*x=22.75*x
21499=22.75x-12x
21499=10.75x
x=21499/10.75≈1999.9≈2000 books
4 0
3 years ago
The shares of the U.S. automobile market held in 1990 by General Motors, Japanese manufacturers, Ford, Chrysler, and other manuf
Mariana [72]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if the purchase frequencies of new-car buyers follow the distribution of the shares of the U.S. automobile market for 1990.

You have one variable of interest:

X: Brand a new-car buyer prefers, categorized: GM, Japanese, Ford, Chrysler and Other

n= 1000

Observed frequencies

GM 193

Japanese 384

Ford 170

Chrysler 90

Other 163

a) The test to use to analyze if the observed purchase frequencies follow the market distribution you have to conduct a Goodness to Fit Chi-Square test.

The conditions for this test are:

- Independent observations

In this case, we will assume that each buyer surveyed is independent of the others.

- For 3+ categories: each expected frequency (Ei) must be at least 1 and at most 20% of the Ei are allowed to be less than 5.

In our case we have a total of 5 categories, 20% of 5 is 1, only one expected frequency is allowed to have a value less than 5.

I'll check this by calculating all expected frequencies using the formula: Ei= n*Pi (Pi= theoretical proportion that corresponds to the i-category)

E(GM)= n*P(GM)= 1000*0.36= 360

E(Jap)= n*P(Jap)= 1000*0.26= 260

E(Ford)= n*P(Ford)= 1000*0.21= 210

E(Chrys)= n*P(Chrys)= 1000*0.09= 90

E(Other)= n*P(Other)= 1000*0.08= 80

Note: If all calculations are done correctly then ∑Ei=n.

This is a quick way to check if the calculations are done correctly.

As you can see all conditions for the test are met.

b) The hypotheses for this test are:

H₀: P(GM)= 0.36; P(Jap)= 0.26; P(Ford)= 0.21; P(Chrys)= 0.09; P(Other)= 0.08

H₁: At least one of the expected frequencies is different from the observed ones.

α: 0.05

X^2= sum \frac{(Oi-Ei)^2}{Ei} ~~X^2_{k-1}

k= number of categories of the variable.

This test is one-tailed right this mean you'll reject the null hypothesis to high values of X²

X^2_{k-1;1-\alpha }= X^2_{4;0.95}= 9.488

Decision rule using the critical value approach:

If X^2_{H_0} ≥ 9.488, reject the null hypothesis

If X^2_{H_0} < 9.488, don't reject the null hypothesis

X^2_{H_0}= \frac{(193-360)^2}{360} + \frac{(384-260)^2}{260} + \frac{(170-210)^2}{210} + \frac{(90-90)^2}{90} + \frac{(163-80)^2}{80} = 230.34

The value of the statistic under the null hypothesis is greater than the critical value, so the decision is to reject the null hypothesis.

Using a 5% level of significance, there is significant evidence to conclude that the current market greatly differs from the preference distribution of 1990.

5 0
3 years ago
You have 40 different books (20 math books, 15 history books, and 5 geography books). a. You pick one book at random. What is th
svetoff [14.1K]

Answer:

a.  \frac{3}{8}

b.  \frac{7}{52}

c.  \frac{95}{156}

Step-by-step explanation:

Given,

Total books = 40,

Maths books = 20,

History books = 15,

Geography books = 5,

a. If a book is randomly selected,

Then the probability that the book is a history book,

=\frac{\text{Ways of choosing history book}}{\text{Ways of choosing any one book}}

=\frac{^{15}C_1}{^{40}C_1}

=\frac{15}{40}

=\frac{3}{8}

b. If two book is randomly selected,

Then the probability that both books are from history,

=\frac{\text{Ways of choosing two history book}}{\text{Ways of choosing any two book}}

=\frac{^{15}C_2}{^{40}C_2}

=\frac{\frac{15!}{2!13!}}{\frac{40!}{2!38!}}

=\frac{105}{780}

=\frac{7}{52}

c. If two book is randomly selected,

Ways of selecting any two books from different subjects

= maths and history + maths and geography + history and geography,

=^{20}C_1\times ^{15}C_1+^{20}C_1\times ^{5}C_1+^{15}C_1\times ^{5}C_1

=20\times 15 + 20\times 5 + 15\times 5

=300 + 100 + 75

=475

Then the probability that both books are from different subjects

=\frac{\text{Ways of selecting any two books from different subjects}}{\text{Ways of choosing any two book}}

=\frac{475}{780}

=\frac{95}{156}

7 0
3 years ago
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