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galben [10]
2 years ago
11

10 years ago a father was 10 times old as his son. Form a linear equation expressing their present age

Mathematics
1 answer:
seropon [69]2 years ago
5 0

x - 10 = 10(x - 10)


Ten years ago, both the father and son were 10 years less.


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Sam traveled 3/4 of a journey by bus. He jogged 1/2 of the remaining distance and walked the rest of the way. If he walked 800 f
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-15.6 = -3.9r<br> please include an explanation of how you got your answer :) thanks
Mumz [18]

Here is the equation:

-15.6 = -3.9r

Since both decimals are negative, the answer will be positive.

  • Negative times Negative = Positive

Divide both sides by -3.9 to leave the variable alone:

-15.6 \div -3.9  = -3.9r \div -3.9 \\ 4 = r

r is equal to 4 → r = 4

5 0
2 years ago
3<br> x<br> +<br> y<br> =<br> −<br> 14<br> 4<br> x<br> +<br> 4<br> y<br> =<br> −<br> 16
aev [14]

Answer:

y=1

x=-5

Step-by-step explanation:

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4(-3x-14)+4x=-16

y=-3x-14

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x=-5

y=1

x=-5

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