Find the total surface area of the following cone. Leave your answer in terms of Pi. 4cm 3cm

Mathematics

1 answer:

castortr0y [4]2 years ago

5 0

The triangle formed from the height of the cone and the radius of its base is a special 3,4,5 triangle. The slant height is 5cm.

Recall that the area of a circle = pi*r^2

Substitute 3 in for r

Area = pi * (3)^2 = 9pi

SA = pi*r*l + B

Substitute our values into the equation

SA = pi * 3 * 5 + 9pi

SA = 15pi + 9pi

SA = 24pi cm^2

You might be interested in

Graph the linear equation. Find three

Sever21 [200]

Y=1/3x+2
(-6,0)
(0,2)
(6,4)

6 0

2 years ago

Which answer shows a correct order to solve this story problem?

Salsk061 [2.6K]

C is correct.
1. You do 12.99 times 3
2. $0.69 times 2
3. Add $2.99 to the two prices above
4. Add the $2.52 tax to the prices
And you should get around $45 and some change

7 0

3 years ago

Mark the sum as either positive or negative

tester [92]

Answer:

1: Positive

2: Negative

3: Negative

4: Negative

Step-by-step explanation:

Positive plus Negative equals negative.

Positive plus positive or negative plus negative equals positive.

Hope this helps.

6 0

2 years ago

Read 2 more answers

Please help, i'm horrible @ math :)

katovenus [111]

$\displaystyle\\
1 \frac{2}{5} +\Big(-5 \frac{1}{2} \Big) = ? \\ \\ 
1 \frac{2}{5} = \frac{1\times 5+2}{5}=\boxed{\frac{7}{5}} \\ \\ 
-5 \frac{1}{2} =-5 -\frac{1}{2} = \frac{-5\times2-1}{2} =\frac{-10-1}{2}=\frac{-11}{2}= \boxed{-\frac{11}{2} }\\ \\ \texttt{OR} \\ \\ 
-5 \frac{1}{2} = -\Big(5 \frac{1}{2} \Big)= -\Big( \frac{5\times2+1}{2} \Big)=-\Big( \frac{11}{2} \Big)= \boxed{-\frac{11}{2} }$

$\displaystyle\\
\Longrightarrow ~~1 \frac{2}{5} +\Big(-5 \frac{1}{2} \Big) =\frac{7}{5} -\frac{11}{2} = \frac{7\times 2}{5\times 2} -\frac{11\times 5}{2\times 5} = \\ \\ 
= \frac{14}{10} -\frac{55}{10} = \frac{14-55}{10} =\frac{-41}{10} = -\frac{41}{10}=-\frac{40+1}{10}=\boxed{\boxed{-4\frac{1}{10}}}$

7 0

3 years ago

Look at the picture of a scaffold used to support construction workers. The height of the scaffold can be changed by adjusting t

timama [110]

Step-by-step explanation:

<u>Using Pythagorus theorem</u> :

(A)

$PR = \sqrt{ {PQ}^{2} + {QR}^{2} }$