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3 years ago

5

I need to know the answer and how to solve this

1 answer:

AURORKA [14]3 years ago

5 0

Answer:

135

Step-by-step explanation:

subtract 180 by 45 since a line is 180, that is what you get for the angle that is adjacent to angle 2, there is a rule if it is adjacent, they equal each other. thus, angle 2 is 135

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Question Of The Day<br><br> 3p - 8 = 13 - 4p<br><br> Show all work & explain how you got it.

Elan Coil [88]

3p-8=13-4p
+4 +4
so now you got 7p-8=13
+8 +8
and now you have 7p=21 and how many times does 7 go in to 21 and you should get p=3 and there you go

3 0

3 years ago

A construction crew must build 4 miles of road in one week. On Monday, they build 12 mile of road. On Tuesday, they build 13 mil

Julli [10]

$\frac{19}{6}$ many more miles of road are left to build .

<u>Step-by-step explanation:</u>

Here we have , A construction crew must build 4 miles of road in one week. On Monday, they build 1/2 mile of road. On Tuesday, they build 1/3 mile of road. We need to find that How many more miles of road are left to build . Let's find out:

On Monday, they build 1/2 mile of road.
On Tuesday, they build 1/3 mile of road.

Let Miles of road left to build is x So,

⇒ $\frac{1}{2} +\frac{1}{3} +x = 4$

⇒ $x = 4 - (\frac{1}{2} +\frac{1}{3})$

⇒ $x = 4 - (\frac{1(3)+1(2)}{6} )$

⇒ $x = 4 - (\frac{5}{6} )$

⇒ $x = (\frac{4(6)-5}{6} )$

⇒ $x = \frac{24-5}{6}$

⇒ $x = \frac{19}{6}$

Therefore, $\frac{19}{6}$ many more miles of road are left to build .

5 0

3 years ago

Read 2 more answers

The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches. Men the same

masha68 [24]

Answer: The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.

Step-by-step explanation:

Let x and y area the random variable that represents the heights of women and men.

Given : The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches.

i.e. $\mu_1 = 64$ $\sigma_1=2.7$

Since , $z=\dfrac{x-\mu}{\sigma}$

Then, z-score corresponds to a woman 6 feet tall (i.e. x=72 inches).

[∵ 1 foot = 12 inches , 6 feet = 6(12)=72 inches]

$z=\dfrac{72-64}{2.7}=2.96296296\approx2.96$

Men the same age have mean height 69.3 inches with standard deviation 2.8 inches.

i.e. $\mu_2 = 69.3$ $\sigma_2=2.8$

Then, z-score corresponds to a man 5'10" tall (i.e. y =70 inches).

[∵ 1 foot = 12 inches , 5 feet 10 inches= 5(12)+10=70 inches]

$z=\dfrac{70-69.3}{2.8}=0.25$

∴ The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.

6 0

3 years ago

30. What is the degree of the polynomial?

zheka24 [161]

Answer:

Step-by-step explanation:

30). $5^{th}$ degree ( 4 + 1 = <em>5</em> ; 1 + 1 = 2 and 2 + 2 = 4 )

31) D) Choice D

4 0

3 years ago

Heeeelp just need 1 and 3

Harlamova29_29 [7]

Answer: I think the answer is. x=y*z I dont know what the verbles are but thats what I got. ANd can you zoom in a bit?

Step-by-step explanation:

4 0

3 years ago