Find x when f(x)=1 . (These means find the input that gives an output of 1.) f(x)=1/x-2

Please help!!!!!! If the measure of angle 8 is 35 what is the measure of angle 4?

saveliy_v [14]

Answer:

It will also be 35

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=48-%2B20" id="TexFormula1" title="48-+20" alt="48-+20" align="absmiddle" class="latex-formula"

poizon [28]

Answer:

240

the always the + and the - = +

so positive plus minus equals positive

5 0

3 years ago

Steve has three boxes. Box A has dimensions that are 5cm by 2cm by 3cm. Box B has dimensions that are 2cm by 2cm by 6cm. Box C h

Vedmedyk [2.9K]

Box A : 5 x 2 x 3 = 30 cubic cm

Box B: 2 x 2 x 6 = 24 cubic cm

Box C: 6 x 3 x 2 = 30 cubic cm

5 0

3 years ago

A sample of 81 account balances of a credit company showed an average balance of $1,200 with a standard deviation of $126.

TEA [102]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ = $1,150

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ $1,150

(b) The test statistic is 3.571.

(c) We conclude that the mean of all account balances is significantly different from $1,150.

Step-by-step explanation:

We are given that a sample of 81 account balances of a credit company showed an average balance of $1,200 with a standard deviation of $126.

We have test the hypothesis to determine whether the mean of all account balances is significantly different from $1,150.

Let $\mu$ = mean of all account balances

(a)So, Null Hypothesis, $H_0$ : $\mu$ = $1,150 {means that the mean of all account balances is equal to $1,150}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ $1,150 {means that the mean of all account balances is significantly different from $1,150}

The test statistics that will be used here is One-sample t test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average balance = $1,200

s = sample standard deviation = $126

n = sample of account balances = 81

(b) So, test statistics = $\frac{1,200-1,150}{\frac{126}{\sqrt{81} } }$ ~ $t_8_0$

= 3.571

The value of the sample test statistics is 3.571.

(c) Now, P-value of the test statistics is given by the following formula;

P-value = P( $t_8_0$ > 3.571) = Less than 0.05%

Because in the t table the highest critical value for t at 80 degree of freedom is given between 3.460 and 3.373 at 0.05% level.

Now, since P-value is less than the level of significance as 5% > 0.05%, so we sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean of all account balances is significantly different from $1,150.

8 0

3 years ago

How would the number of times edgardo uses a container to fill the 10 gallon cooler change if he uses a one cup container? Expla

olya-2409 [2.1K]

Answer:

Edgardo would use the container 160 times to fill.

Step-by-step explanation:

Given:

Edgardo uses a container to fill the 10 gallon cooler.

If he uses a one cup container.

Now, to find the times it would take to fill the 10 gallon container.

As, the capacity of container = 1 cup.

And, the capacity of cooler = 10 gallon.

So, we use conversion factor to find the times the container to fill the cooler:

1 gallon = 16 cups.

10 gallon = $10\times 16\ cups.$

10 gallon = 160 cups.

Thus, to fill the 10 gallon cooler 160 cups of container needed.

And, the container is of 1 cup.

So, to get the times he would use the container we divide 160 by 1:

$160\div 1=160.$

Hence, 160 times Edgardo would use the 1 cup container to fill the 10 gallon cooler.

Therefore, Edgardo would use the container 160 times to fill.

8 0

3 years ago