Bob is filling his 7000-gallon swimming
1 answer:
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<u><em>Answer:</em></u>
Area of rhombus = 126 m²
<u><em>Explanation:</em></u>
<u>We are given that the two diagonals of the rhombus are:</u>
D₁ = 14 meters and D₂ = 18 meters
<u>The area of the rhombus using its diagonals can be calculated using the following rule:</u>
<u>Substitute with the given values to get the area as follows:</u>
Hope this helps :)
So I'm going to assume that this question is asking for <u>non extraneous solutions</u>, or solutions that are found in the equation <em>and</em> are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:
Next, square both sides:
Next, subtract x and add 2 to both sides of the equation:
Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:
Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:
Now you can rewrite the equation as
Now, apply the Zero Product Property and solve for x as such:
Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:
Since both solutions hold true when x = 2 and x = 3, <u>your answer is C. x = 2 or x = 3.</u>