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3 years ago

9

The exact average of a set of six test scores is 92. Five of these scores are 90, 98, 96, 94, and 85. What is the other test sco

re?

1 answer:

nordsb [41]3 years ago

8 0

Answer:

89

Step-by-step explanation:

92 = (90 + 98 + 96+ 94 + 85 + x )/6

92*6 = 90 + 98 + 96+ 94 + 85 + x

552 - (90 + 98 + 96+ 94 + 85) = x

x = 89

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ILL GIVE U STUFFFFF PLZZZZZZZZZZZ ANSWER ITTTTTTTTT

belka [17]

Answer:

Slope: $-\frac{3}{4}$

Y-intercept: 399

Slope-intercept form: $y=-\frac{3}{4}x+399$

Step-by-step explanation:

1. The equation in Standard form is given in the problem:

$3y+4y=1596$

2. Then, to write the equation of the line in slope-intercept form $y=mx+b$ , where <em>m</em> is the slope and <em>b</em> is the y-intercept, you must solve for <em>y</em> as you can see below:

$4y=-3x+1596\\y=\frac{-3x+1596}{4}\\y=-\frac{3}{4}x+399$

3. Therefore, the slope and the y-intercept are:

$m=-\frac{3}{4}\\b=399$

5 0

3 years ago

What is the probability that the product of two dice is greater than<br> 15 on two separate rolls?

ratelena [41]

Answer:

25/324

Step-by-step explanation:

Make a table of possible products:

$\left[\begin{array}{ccccccc}&1&2&3&4&5&6\\1&1&2&3&4&5&6\\2&2&4&6&8&10&12\\3&3&6&9&12&15&18\\4&4&8&12&16&20&24\\5&5&10&15&20&25&30\\6&6&12&18&24&30&36\end{array}\right]$

Of the 36 results, 10 are greater than 15.

The probability the product is greater than 15 on a single roll is 10/36 = 5/18.

The probability the product is greater than 15 on two rolls is (5/18)² = 25/324.

4 0

3 years ago

Is 60:45 and 4:3 are equivalent ratios<br>

WARRIOR [948]

Answer:

yes

Step-by-step explanation:

if we divide both terms of 60 and 45 by 15, we can simplify it to 4:3.

6 0

2 years ago

Help plz!!!!!!!!!!!!!!!!

Elena L [17]

If you can tell us what you need im sure you can get help asap

4 0

3 years ago

REY [17]

Answer:

The probability that a randomly selected point within the circle falls in the red shaded area is p=0.75.

Step-by-step explanation:

We have to calculate the probability that a randomly selected point within the circle falls in the red shaded area.

This probability can be calculated as the quotient between the red shaded area, that is a regular pentagon inscribed in the circle, and the area of the circle.

We start by calculating the area of the circle:

$A_c=\pi r^2\approx 3.14(4)^2=3.14\cdot 16=50.24$

Then, we can calculate the area of the pentagon as:

$A_p=\dfrac{1}{2}\cdot (5a)\cdot S=\dfrac{1}{2}\cdot (5\cdot3.2)\cdot 4.7=37.6$

Then, we can calculate the probability p as the quotient between the areas:

$p=\dfrac{A_p}{A_c}=\dfrac{37.6}{50.24}\approx 0.75$

8 0

3 years ago