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ValentinkaMS [17]
3 years ago
7

ʖ≖hi how are you and do u need help a homework?

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
8 0

Yes if you could help that would be so nice!!!!

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How do you answer this?
lidiya [134]
(a + b)^3 = a^3 + 3a^2b + 3ab^2+ b^3 
(a +(- b))^3 = (a-b)^2 =  a^3 - 3a^2b + 3ab^2- b^3  
7 0
3 years ago
Please help asap 45 pts
trapecia [35]
C) if you multiply it you get w^2 + 7w +11w+77, which is w^2+18w+77
7 0
3 years ago
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Plzzz help me with numbers 6 and 10!!!!!!
sukhopar [10]

see attached picture for #6


10 the inequality would be :

 12 inch box is x

15 inch box is y

12x+15y≤84

6 0
3 years ago
What is the answer to this?
NARA [144]

Answer:

See work for 3 answers

Step-by-step explanation:

You can add the exponents

(-8)^{12}

also could be stated as

(8)^{12}

numerical value

6.87194767 × 10^{10}

5 0
3 years ago
The following are the number of birth per year per 1,000 population for 20 countries: 34, 24, 10, 15, 22, 15, 17, 22, 10, 17, 25
Anna35 [415]

Answer:

A. D = None of the above

B. B = 18

C. A = 15

D. D = None of the above

Step-by-step explanation:

Rearranging the population from the highest to the lowest.

10, 10, 12, 15, 15, 15, 15, 17, 17, 18, 18, 20, 22, 22, 24, 25, 31, 32, 34, 37

Mean = (summation of all the 20 samples)/ no of samples

Mean per year per 1000 population = 409/20

= 20.45

Median = the middle value (for odd numbered samples)

= the sum of the middle value ÷ 2 ( for even numbered samples)

Median birth per year per 1000 population = (18 + 18)/2

= 18

Mode = the sample that has the number of frequency

Mode per year per 1000 population = 15 (frequency = 4)

Range = highest value sample - lowest value sample

Range per year per 1000 population = 37 - 10

= 27

6 0
3 years ago
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